Answered

The Rocket Club is planning to launch a pair of model rockets. To build the rocket, the club needs a rocket body paired with an engine. The table lists the mass of three possible rocket bodies and the force generated by three possible engines.

\begin{tabular}{|c|c|c|c|}
\hline
Body & Mass (kg) & Engine & Force (N) \\
\hline
1 & 0.500 & 1 & 25 \\
\hline
2 & 1.5 & 2 & 20 \\
\hline
3 & 0.750 & 3 & 30 \\
\hline
\end{tabular}

Based on Newton's laws of motion, which combination of rocket bodies and engines will result in the acceleration of [tex]$40 \, m/s^2$[/tex] at the start of the launch?

A. Body 3 + Engine 1
B. Body 2 + Engine 2
C. Body 1 + Engine 2
D. Body 1 + Engine 1



Answer :

To find which combination of rocket bodies and engines will result in an acceleration of [tex]\(40 \, \text{m/s}^2\)[/tex] at the start of the launch, we need to use Newton's second law of motion, which states that:

[tex]\[ a = \frac{F}{m} \][/tex]

where [tex]\( a \)[/tex] is acceleration, [tex]\( F \)[/tex] is the force, and [tex]\( m \)[/tex] is the mass. We will calculate the acceleration for each combination of body and engine and check which one meets the required acceleration of [tex]\( 40 \, \text{m/s}^2 \)[/tex].

Step-by-Step Solution:

1. Computation for Body 1 and Engine 1:
- Mass of Body 1, [tex]\( m_1 = 0.500 \, \text{kg} \)[/tex]
- Force of Engine 1, [tex]\( F_1 = 25 \, \text{N} \)[/tex]
- Acceleration:
[tex]\[ a = \frac{F_1}{m_1} = \frac{25}{0.500} = 50 \, \text{m/s}^2 \][/tex]
- This combination does not meet the required acceleration of [tex]\( 40 \, \text{m/s}^2 \)[/tex].

2. Computation for Body 1 and Engine 2:
- Mass of Body 1, [tex]\( m_1 = 0.500 \, \text{kg} \)[/tex]
- Force of Engine 2, [tex]\( F_2 = 20 \, \text{N} \)[/tex]
- Acceleration:
[tex]\[ a = \frac{F_2}{m_1} = \frac{20}{0.500} = 40 \, \text{m/s}^2 \][/tex]
- This combination meets the required acceleration of [tex]\( 40 \, \text{m/s}^2 \)[/tex].

3. Computation for Body 2 and Engine 2:
- Mass of Body 2, [tex]\( m_2 = 1.5 \, \text{kg} \)[/tex]
- Force of Engine 2, [tex]\( F_2 = 20 \, \text{N} \)[/tex]
- Acceleration:
[tex]\[ a = \frac{F_2}{m_2} = \frac{20}{1.5} \approx 13.33 \, \text{m/s}^2 \][/tex]
- This combination does not meet the required acceleration of [tex]\( 40 \, \text{m/s}^2 \)[/tex].

4. Computation for Body 3 and Engine 1:
- Mass of Body 3, [tex]\( m_3 = 0.750 \, \text{kg} \)[/tex]
- Force of Engine 1, [tex]\( F_1 = 25 \, \text{N} \)[/tex]
- Acceleration:
[tex]\[ a = \frac{F_1}{m_3} = \frac{25}{0.750} \approx 33.33 \, \text{m/s}^2 \][/tex]
- This combination does not meet the required acceleration of [tex]\( 40 \, \text{m/s}^2 \)[/tex].

After evaluating all possible combinations, we find that the combination which results in the required acceleration of [tex]\( 40 \, \text{m/s}^2 \)[/tex] is:

Body 1 + Engine 2