A company makes cone-shaped, solid glass paperweights with a square photo attached to the base. The paperweights come in a variety of sizes, and the glass used has a density of 3 grams per cubic centimeter. The following expression gives the total mass of a paperweight with a height of [tex]$h$[/tex] centimeters and uses 3.14 as an estimate for pi.

[tex]
3.14 h^3 - 25.12 h^2 + 50.24 h
[/tex]

Which of the following is the best interpretation of the factor [tex]$3.14(h-4)^2$[/tex]?

A. The lateral area of the paperweight

B. The area of the photo attached to the base of the paperweight

C. The surface area of the paperweight

D. The area of the base of the paperweight



Answer :

To solve the problem, we need to understand the given expression and interpret what each factor represents.

The given expression for the total mass of the paperweight is:
[tex]\[ 3.14 h^3 - 25.12 h^2 + 50.24 h \][/tex]

Let's focus on interpreting the factor [tex]\(3.14(h-4)^2\)[/tex].

We know that [tex]\(3.14\)[/tex] is an approximation of the mathematical constant [tex]\(\pi\)[/tex], which is commonly used in geometry to calculate areas and volumes involving circles and spheres.

Given the context of the problem, which involves a cone-shaped paperweight, let's consider what [tex]\( (h-4)^2 \)[/tex] might represent within this framework.

For a cone, the area of the base is calculated by the formula:
[tex]\[ \text{Area} = \pi r^2 \][/tex]
where [tex]\( r \)[/tex] is the radius of the base.

Given the factor [tex]\( 3.14(h-4)^2 \)[/tex], we can compare this to the formula for the area of the base of a cone:
[tex]\[ 3.14 \times (\text{radius})^2 \][/tex]

To interpret [tex]\( (h-4) \)[/tex], consider that it is most likely representing the radius of the base of the cone. Thus,
[tex]\[ 3.14(h-4)^2 \][/tex]
fits the form of [tex]\(\pi r^2 \)[/tex], which is indeed the area of the circular base of the paperweight.

Therefore, the best interpretation of the factor [tex]\( 3.14(h-4)^2 \)[/tex] is:

D. the area of the base of the paperweight.