Answer :
To determine the best conclusion supported by the data in the chart, let's analyze the information provided about the object's motion.
The data in the chart shows the velocity of the object at different times:
[tex]\[ \begin{array}{|c|c|} \hline \text{Time (s)} & \text{Velocity (m/s)} \\ \hline 2 & 8 \\ \hline 4 & 8 \\ \hline 6 & 8 \\ \hline \end{array} \][/tex]
From this data, we can observe the following:
1. Velocity at Different Times:
- At [tex]\( t = 2 \, \text{s} \)[/tex], the velocity is [tex]\( 8 \, \text{m/s} \)[/tex].
- At [tex]\( t = 4 \, \text{s} \)[/tex], the velocity is [tex]\( 8 \, \text{m/s} \)[/tex].
- At [tex]\( t = 6 \, \text{s} \)[/tex], the velocity is [tex]\( 8 \, \text{m/s} \)[/tex].
2. Change in Velocity:
The velocity remains constant at [tex]\( 8 \, \text{m/s} \)[/tex] throughout the time period given.
With these observations, let's evaluate the possible conclusions:
- Negative Displacement:
Displacement is dependent on the change in position over time. The data does not provide information about the change in position, only about the velocity. Therefore, we cannot conclude on displacement from the given data.
- Negative Acceleration:
Acceleration refers to the rate of change of velocity with respect to time. Since the velocity remains constant at [tex]\( 8 \, \text{m/s} \)[/tex] and does not change over time, the object does not have any acceleration, positive or negative.
- No Displacement:
Displacement involves assessing how far the object has moved from its initial position. We cannot determine the displacement from the given velocity data alone without additional information about the initial and final positions.
- Not Accelerating:
Since the velocity remains constant and does not change over time, we can conclude that the object is not accelerating.
Therefore, the conclusion best supported by the information in the chart is:
The object is not accelerating.
The data in the chart shows the velocity of the object at different times:
[tex]\[ \begin{array}{|c|c|} \hline \text{Time (s)} & \text{Velocity (m/s)} \\ \hline 2 & 8 \\ \hline 4 & 8 \\ \hline 6 & 8 \\ \hline \end{array} \][/tex]
From this data, we can observe the following:
1. Velocity at Different Times:
- At [tex]\( t = 2 \, \text{s} \)[/tex], the velocity is [tex]\( 8 \, \text{m/s} \)[/tex].
- At [tex]\( t = 4 \, \text{s} \)[/tex], the velocity is [tex]\( 8 \, \text{m/s} \)[/tex].
- At [tex]\( t = 6 \, \text{s} \)[/tex], the velocity is [tex]\( 8 \, \text{m/s} \)[/tex].
2. Change in Velocity:
The velocity remains constant at [tex]\( 8 \, \text{m/s} \)[/tex] throughout the time period given.
With these observations, let's evaluate the possible conclusions:
- Negative Displacement:
Displacement is dependent on the change in position over time. The data does not provide information about the change in position, only about the velocity. Therefore, we cannot conclude on displacement from the given data.
- Negative Acceleration:
Acceleration refers to the rate of change of velocity with respect to time. Since the velocity remains constant at [tex]\( 8 \, \text{m/s} \)[/tex] and does not change over time, the object does not have any acceleration, positive or negative.
- No Displacement:
Displacement involves assessing how far the object has moved from its initial position. We cannot determine the displacement from the given velocity data alone without additional information about the initial and final positions.
- Not Accelerating:
Since the velocity remains constant and does not change over time, we can conclude that the object is not accelerating.
Therefore, the conclusion best supported by the information in the chart is:
The object is not accelerating.