```latex
\begin{tabular}{|c|c|}
\hline [tex]$x$[/tex] & [tex]$y$[/tex] \\
\hline
-3 & 2 \\
\hline
-2 & 0 \\
\hline
-1 & 0 \\
\hline
0 & 2 \\
\hline
1 & 6 \\
\hline
2 & 12 \\
\hline
3 & 20 \\
\hline
\end{tabular}
```



Answer :

To analyze the given table of [tex]\( x \)[/tex] and [tex]\( y \)[/tex] values, follow these steps:

1. Understand the Data:
- We have pairs of [tex]\( x \)[/tex] and [tex]\( y \)[/tex] values as follows:
- When [tex]\( x = -3 \)[/tex], [tex]\( y = 2 \)[/tex]
- When [tex]\( x = -2 \)[/tex], [tex]\( y = 0 \)[/tex]
- When [tex]\( x = -1 \)[/tex], [tex]\( y = 0 \)[/tex]
- When [tex]\( x = 0 \)[/tex], [tex]\( y = 2 \)[/tex]
- When [tex]\( x = 1 \)[/tex], [tex]\( y = 6 \)[/tex]
- When [tex]\( x = 2 \)[/tex], [tex]\( y = 12 \)[/tex]
- When [tex]\( x = 3 \)[/tex], [tex]\( y = 20 \)[/tex]

2. Identify Patterns:
- Look at the changes in [tex]\( y \)[/tex] for each successive value of [tex]\( x \)[/tex].

3. Calculate Differences:
- First differences:
- [tex]\( y(-2) - y(-3) = 0 - 2 = -2 \)[/tex]
- [tex]\( y(-1) - y(-2) = 0 - 0 = 0 \)[/tex]
- [tex]\( y(0) - y(-1) = 2 - 0 = 2 \)[/tex]
- [tex]\( y(1) - y(0) = 6 - 2 = 4 \)[/tex]
- [tex]\( y(2) - y(1) = 12 - 6 = 6 \)[/tex]
- [tex]\( y(3) - y(2) = 20 - 12 = 8 \)[/tex]

- Second differences (checking for a constant second difference, which indicates a quadratic relationship):
- [tex]\( 0 - (-2) = 2 \)[/tex]
- [tex]\( 2 - 0 = 2 \)[/tex]
- [tex]\( 4 - 2 = 2 \)[/tex]
- [tex]\( 6 - 4 = 2 \)[/tex]
- [tex]\( 8 - 6 = 2 \)[/tex]

4. Conclusion:
- The constant second difference suggests [tex]\( y \)[/tex] could be represented as a quadratic function of [tex]\( x \)[/tex].

Understanding the relationship between [tex]\( x \)[/tex] and [tex]\( y \)[/tex] based on the observations can be summarized thus:

- As [tex]\( x \)[/tex] transitions from [tex]\(-3\)[/tex] to [tex]\(3\)[/tex], the corresponding [tex]\( y \)[/tex] values evolve in accordance with a quadratic pattern, as indicated by the constant second differences.