Solve the following expressions:

1. [tex]\(\square - 8 = 19\)[/tex]
2. [tex]\( \square + \square = 16 \)[/tex]
3. [tex]\( \square + \square = ? \)[/tex]

(Note: Ensure that the correct solution for [tex]\(\square\)[/tex] is used consistently across all expressions.)



Answer :

Let's break down the given equations step by step and solve for the unknowns.

1. First Equation: [tex]\(\square - 8 = 19\)[/tex]

To find the value of [tex]\(\square\)[/tex], we need to isolate [tex]\(\square\)[/tex] on one side of the equation. To do this, we can add 8 to both sides of the equation:

[tex]\[ \square - 8 + 8 = 19 + 8 \][/tex]

Simplifying this, we get:

[tex]\[ \square = 27 \][/tex]

So, [tex]\(\square = 27\)[/tex].

2. Second Equation: [tex]\(+==16\)[/tex]

Without additional context or any other operations described, we assume this indicates another value set equal to 16. Let’s denote this new value by [tex]\(y\)[/tex]:

[tex]\[ y = 16 \][/tex]

3. Third Equation: [tex]\(+==?\)[/tex]

There’s ambiguity in the interpretation of this equation. As no clear operation or additional context is provided, we can assume that this equation might be unrelated or it’s simply asking us to state the previously calculated values.

Given the values from the above steps:

- The value of [tex]\(\square\)[/tex] (which was represented by [tex]\(x\)[/tex] ) is [tex]\(27\)[/tex].
- The value [tex]\(y\)[/tex] is [tex]\(16\)[/tex].

Thus, the final result based on the equations provided is:

[tex]\[ \square = 27 \quad \text{and} \quad y = 16 \][/tex]