To find the mass of silver (Ag) that occupies a certain volume, you can use the formula for density, which is defined as:
[tex]\[ \text{Density} = \frac{\text{Mass}}{\text{Volume}} \][/tex]
In this problem, we are given the density of silver and the volume it occupies. We need to find the mass. Rearranging the formula to solve for mass, we get:
[tex]\[ \text{Mass} = \text{Density} \times \text{Volume} \][/tex]
Given:
- The density of silver (Ag) is [tex]\( 10.5 \, \text{g/cm}^3 \)[/tex].
- The volume of silver is [tex]\( 965 \, \text{cm}^3 \)[/tex].
Now, substitute the given values into the equation to find the mass:
[tex]\[ \text{Mass} = 10.5 \, \text{g/cm}^3 \times 965 \, \text{cm}^3 \][/tex]
By performing the multiplication, you find:
[tex]\[ \text{Mass} = 10132.5 \, \text{g} \][/tex]
Therefore, the mass of silver that occupies [tex]\( 965 \, \text{cm}^3 \)[/tex] of space is [tex]\( 10132.5 \, \text{g} \)[/tex].
