To test the model, students collected data from five different high schools in their area. On the table, choose the schools for which the model is significantly different from the experimental probability for choosing a red car.

Select the correct locations on the table.

\begin{tabular}{|l|c|c|c|c|}
\hline School & Blue & Red & White & Total \\
\hline East Bank High & 36 & 19 & 31 & 86 \\
\hline South High & 19 & 11 & 17 & 47 \\
\hline Mountain View High & 23 & 4 & 15 & 42 \\
\hline Day Spring High & 52 & 18 & 40 & 110 \\
\hline Hinckley High & 60 & 33 & 51 & 144 \\
\hline
\end{tabular}



Answer :

To determine if the model is significantly different from the experimental probability for choosing a red car in the various schools, we first gather the relevant data and then perform a Chi-square test. Based on the provided results, we will identify the significant schools.

Here's the data given for each school:

- East Bank High:
- Red cars: 19
- Total cars: 86

- South High:
- Red cars: 11
- Total cars: 47

- Mountain View High:
- Red cars: 4
- Total cars: 42

- Day Spring High:
- Red cars: 18
- Total cars: 110

- Hinckley High:
- Red cars: 33
- Total cars: 144

First, calculate the overall totals from all schools:

- Total number of red cars observed: [tex]\( 19 + 11 + 4 + 18 + 33 = 85 \)[/tex]
- Total number of cars observed: [tex]\( 86 + 47 + 42 + 110 + 144 = 429 \)[/tex]

Next, we find the expected number of red cars for each school using the ratio of total red cars to total cars:

- Expected number of red cars at East Bank High: [tex]\( \frac{85}{429} \times 86 \approx 17.04 \)[/tex]
- Expected number of red cars at South High: [tex]\( \frac{85}{429} \times 47 \approx 9.31 \)[/tex]
- Expected number of red cars at Mountain View High: [tex]\( \frac{85}{429} \times 42 \approx 8.32 \)[/tex]
- Expected number of red cars at Day Spring High: [tex]\( \frac{85}{429} \times 110 \approx 21.79 \)[/tex]
- Expected number of red cars at Hinckley High: [tex]\( \frac{85}{429} \times 144 \approx 28.53 \)[/tex]

Perform the Chi-square goodness of fit test:

- Chi-square test statistic: 4.136
- p-value: 0.388

A p-value of 0.388 indicates that there is no significant difference between the observed and the expected number of red cars in any of the schools, as the p-value is much higher than 0.05.

Thus, none of the schools show a statistically significant difference from the experimental probability for choosing a red car. Therefore, based on the data and chi-square test results, none of the schools should be selected as having a model significantly different from the experimental probability.