Question 3 (Multiple Choice, Worth 2 Points)

Using a standard deck of 52 cards, Lisa drew a card, recorded the suit of the card picked, then replaced it back in the deck. She continued this for a total of 40 draws. The table below shows the frequency of each type of card drawn.

[tex]\[
\begin{tabular}{|l|l|l|l|}
\hline
Diamonds & Spades & Hearts & Clubs \\
\hline
7 & 11 & 9 & 13 \\
\hline
\end{tabular}
\][/tex]

Determine the experimental probability of not selecting a diamond.

A. [tex]$P($[/tex] not diamond [tex]$)=82.5\%$[/tex]

B. [tex]$P($[/tex] not diamond [tex]$)=72.5\%$[/tex]

C. [tex]$P($[/tex] not diamond [tex]$)=10\%$[/tex]

D. [tex]$P($[/tex] not diamond [tex]$)=7\%$[/tex]



Answer :

To determine the experimental probability of not selecting a diamond from Lisa's draws, let's follow the step-by-step solution:

1. Identify the Total Number of Draws:
Lisa performed a total of 40 draws.

2. Identify the Number of Diamond Draws:
According to the given data, the number of times a diamond was drawn is 7.

3. Calculate the Number of Non-Diamond Draws:
To find out how many draws were not diamonds, we subtract the number of diamond draws from the total number of draws:
[tex]\[ \text{Number of non-diamond draws} = \text{Total number of draws} - \text{Number of diamond draws} \][/tex]
[tex]\[ \text{Number of non-diamond draws} = 40 - 7 = 33 \][/tex]

4. Calculate the Experimental Probability:
The experimental probability of an event is given by the ratio of the number of successful outcomes (in this case, not drawing a diamond) to the total number of trials (total draws). Here, we are interested in the probability of not drawing a diamond:
[tex]\[ P(\text{not diamond}) = \frac{\text{Number of non-diamond draws}}{\text{Total number of draws}} \][/tex]
[tex]\[ P(\text{not diamond}) = \frac{33}{40} \][/tex]

5. Express the Probability as a Percentage:
To convert this fraction to a percentage, we multiply by 100:
[tex]\[ P(\text{not diamond}) = \left( \frac{33}{40} \right) \times 100 = 82.5\% \][/tex]

Thus, the experimental probability of not selecting a diamond is [tex]\( 82.5\% \)[/tex].

So, the correct answer is:
[tex]\[ P(\text{not diamond}) = 82.5\% \][/tex]