9.
a) The sum of two numbers is 10, and the sum of their squares is 68.
(i) If one of the numbers is [tex]\(x\)[/tex], write the other number in terms of [tex]\(x\)[/tex].
(ii) Find the numbers.
(iii) Find the ratio of the sum to the product of the numbers.

40.
(iii) By what percent is the sum of two numbers whose product is 4 and the sum of their squares is 40?



Answer :

Sure! Let's go step by step to solve this problem.

### Given:

a) The sum of two numbers is 10 and the sum of their squares is 68.

#### (i) If one of the numbers is [tex]\( x \)[/tex], write the other number in terms of [tex]\( x \)[/tex].

If one of the numbers is [tex]\( x \)[/tex], then the other number can be written as [tex]\( 10 - x \)[/tex], since the sum of the two numbers is 10.

#### (ii) Find the numbers.

We need two equations here:

1. The sum of the numbers:
[tex]\[ x + (10 - x) = 10 \][/tex]

2. The sum of their squares:
[tex]\[ x^2 + (10 - x)^2 = 68 \][/tex]

Let's simplify the second equation step-by-step:

[tex]\[ x^2 + (10 - x)^2 = 68 \][/tex]

Expand [tex]\( (10 - x)^2 \)[/tex]:

[tex]\[ (10 - x)^2 = 100 - 20x + x^2 \][/tex]

So the equation becomes:

[tex]\[ x^2 + 100 - 20x + x^2 = 68 \][/tex]

Combine like terms:

[tex]\[ 2x^2 - 20x + 100 = 68 \][/tex]

Subtract 68 from both sides to set the equation to zero:

[tex]\[ 2x^2 - 20x + 32 = 0 \][/tex]

This is a quadratic equation [tex]\( 2x^2 - 20x + 32 = 0 \)[/tex].

To solve the quadratic equation, we use the quadratic formula [tex]\( x = \frac{{-b \pm \sqrt{{b^2 - 4ac}}}}{2a} \)[/tex], where [tex]\( a = 2 \)[/tex], [tex]\( b = -20 \)[/tex], and [tex]\( c = 32 \)[/tex].

Calculate the discriminant:

[tex]\[ b^2 - 4ac = (-20)^2 - 4 \cdot 2 \cdot 32 = 400 - 256 = 144 \][/tex]

Now find the roots:

[tex]\[ x = \frac{{20 \pm \sqrt{144}}}{4} \][/tex]

[tex]\[ x = \frac{{20 \pm 12}}{4} \][/tex]

So, we get two solutions:

[tex]\[ x_1 = \frac{{20 + 12}}{4} = \frac{32}{4} = 8 \][/tex]

[tex]\[ x_2 = \frac{{20 - 12}}{4} = \frac{8}{4} = 2 \][/tex]

The numbers are 8 and 2.

#### (iii) Find the ratio of the sum to the product of the numbers.

The sum of the numbers is:

[tex]\[ 8 + 2 = 10 \][/tex]

The product of the numbers is:

[tex]\[ 8 \times 2 = 16 \][/tex]

The ratio of the sum to the product is:

[tex]\[ \frac{{\text{sum of the numbers}}}{{\text{product of the numbers}}} = \frac{10}{16} = 0.625 \][/tex]

So, the ratio of the sum to the product of the numbers is [tex]\( 0.625 \)[/tex].

### Summary:
1. The numbers are 8 and 2.
2. The ratio of the sum to the product of the numbers is [tex]\( 0.625 \)[/tex].