Answer :
To find the value of [tex]\( i^7 \)[/tex], we need to understand the properties of powers of the imaginary unit [tex]\( i \)[/tex]. The imaginary unit [tex]\( i \)[/tex] has a cyclical pattern in its powers, repeating every four terms. This cyclical pattern is as follows:
[tex]\[ \begin{align*} i^1 & = i, \\ i^2 & = -1, \\ i^3 & = -i, \\ i^4 & = 1, \\ i^5 & = i, \\ i^6 & = -1, \\ i^7 & = -i, \\ i^8 & = 1, \quad \text{and so on.} \end{align*} \][/tex]
Notice that every four powers, the pattern repeats itself: [tex]\( i, -1, -i, 1 \)[/tex].
To determine [tex]\( i^7 \)[/tex], we can first simplify the exponent 7 in terms of this 4-term cycle. We do this by finding the remainder when 7 is divided by 4:
[tex]\[ 7 \div 4 = 1 \text{ with a remainder of } 3. \][/tex]
This remainder tells us the equivalent power within one full cycle. Specifically, the remainder 3 indicates that [tex]\( i^7 \)[/tex] is equivalent to [tex]\( i^3 \)[/tex].
From the established cycle, we know that:
[tex]\[ i^3 = -i. \][/tex]
Therefore, the value of [tex]\( i^7 \)[/tex] is:
[tex]\[ \boxed{-i}. \][/tex]
So the correct answer is:
(C) [tex]\( -i \)[/tex].
[tex]\[ \begin{align*} i^1 & = i, \\ i^2 & = -1, \\ i^3 & = -i, \\ i^4 & = 1, \\ i^5 & = i, \\ i^6 & = -1, \\ i^7 & = -i, \\ i^8 & = 1, \quad \text{and so on.} \end{align*} \][/tex]
Notice that every four powers, the pattern repeats itself: [tex]\( i, -1, -i, 1 \)[/tex].
To determine [tex]\( i^7 \)[/tex], we can first simplify the exponent 7 in terms of this 4-term cycle. We do this by finding the remainder when 7 is divided by 4:
[tex]\[ 7 \div 4 = 1 \text{ with a remainder of } 3. \][/tex]
This remainder tells us the equivalent power within one full cycle. Specifically, the remainder 3 indicates that [tex]\( i^7 \)[/tex] is equivalent to [tex]\( i^3 \)[/tex].
From the established cycle, we know that:
[tex]\[ i^3 = -i. \][/tex]
Therefore, the value of [tex]\( i^7 \)[/tex] is:
[tex]\[ \boxed{-i}. \][/tex]
So the correct answer is:
(C) [tex]\( -i \)[/tex].