The probability of event [tex]$A$[/tex] is [tex]$x$[/tex], and the probability of event [tex][tex]$B$[/tex][/tex] is [tex]$y$[/tex]. If the two events are independent, which condition must be true?

A. [tex]$P (A \mid B)=x$[/tex]
B. [tex][tex]$P (A \mid B)=y$[/tex][/tex]
C. [tex]$P (B \mid A)=x$[/tex]
D. [tex]$P(B \mid A)=xy$[/tex]



Answer :

To determine the correct condition that must be true when events [tex]\( A \)[/tex] and [tex]\( B \)[/tex] are independent, let’s start by revisiting the definition of independent events in probability.

### Definition of Independent Events

Two events [tex]\( A \)[/tex] and [tex]\( B \)[/tex] are said to be independent if the occurrence of one event does not affect the probability of the other event occurring. Mathematically, this is expressed as:
[tex]\[ P(A \cap B) = P(A) \cdot P(B) \][/tex]

Additionally, for independent events [tex]\( A \)[/tex] and [tex]\( B \)[/tex]:
[tex]\[ P(A \mid B) = P(A) \][/tex]
[tex]\[ P(B \mid A) = P(B) \][/tex]

### Analyzing Each Option

Let’s analyze each option given in the question:

A. [tex]\( P(A \mid B) = x \)[/tex]

Since [tex]\( x \)[/tex] represents [tex]\( P(A) \)[/tex] and knowing that [tex]\( P(A \mid B) = P(A) \)[/tex], we can rewrite this as:
[tex]\[ P(A \mid B) = P(A) \][/tex]
Thus, this condition simplifies to:
[tex]\[ P(A \mid B) = x \][/tex]
This condition is true for independent events.

B. [tex]\( P(A \mid B) = y \)[/tex]

Here, [tex]\( y \)[/tex] represents [tex]\( P(B) \)[/tex]. For independent events, [tex]\( P(A \mid B) \)[/tex] should equal [tex]\( P(A) \)[/tex] and not [tex]\( P(B) \)[/tex]. Therefore:
[tex]\[ P(A \mid B) \neq P(B) \][/tex]
This condition is false for independent events.

C. [tex]\( P(B \mid A) = x \)[/tex]

In this case, [tex]\( x \)[/tex] still represents [tex]\( P(A) \)[/tex]. For independent events, [tex]\( P(B \mid A) \)[/tex] should equal [tex]\( P(B) \)[/tex] and not [tex]\( P(A) \)[/tex]. Thus:
[tex]\[ P(B \mid A) \neq P(A) \][/tex]
This condition is false for independent events.

D. [tex]\( P(B \mid A) = xy \)[/tex]

This implies that [tex]\( P(B \mid A) \)[/tex] is equal to the product of [tex]\( P(A) \)[/tex] and [tex]\( P(B) \)[/tex]. For independent events, we know:
[tex]\[ P(B \mid A) = P(B) \][/tex]
Therefore, equating it to [tex]\( xy \)[/tex] would not be correct:
[tex]\[ P(B \mid A) \neq P(A) \cdot P(B) \][/tex]
This condition is false for independent events.

### Conclusion

Based on the analysis above, the correct condition that must be true when events [tex]\( A \)[/tex] and [tex]\( B \)[/tex] are independent is:

A. [tex]\( P(A \mid B) = x \)[/tex]