Let's solve the problem step by step based on the given data.
### Step 1: Analyze Burette Readings
We will calculate the volumes of [tex]\( NaOH \)[/tex] added for each trial:
#### Trial 1:
- Initial burette reading: [tex]\( 0.00 \, ml \)[/tex]
- Final burette reading: [tex]\( 24.10 \, ml \)[/tex]
- Volume added: [tex]\( 24.10 \, ml - 0.00 \, ml = 24.10 \, ml \)[/tex]
#### Trial 2:
- Initial burette reading: [tex]\( 24.10 \, ml \)[/tex]
- Final burette reading: [tex]\( 47.20 \, ml \)[/tex]
- Volume added: [tex]\( 47.20 \, ml - 24.10 \, ml = 23.10 \, ml \)[/tex]
#### Trial 3:
- Initial burette reading: [tex]\( 0.00 \, ml \)[/tex]
- Final burette reading: [tex]\( 23.70 \, ml \)[/tex]
- Volume added: [tex]\( 23.70 \, ml - 0.00 \, ml = 23.70 \, ml \)[/tex]
### Step 2: Collate the Volumes Added
Summarize the volumes added for each trial:
- Trial 1: [tex]\( 24.10 \, ml \)[/tex]
- Trial 2: [tex]\( 23.10 \, ml \)[/tex]
- Trial 3: [tex]\( 23.70 \, ml \)[/tex]
The volumes added are:
[tex]\[ [24.1, 23.1, 23.7] \][/tex]
### Step 3: Calculate the Total Volume Added
The total volume of [tex]\( NaOH \)[/tex] added is the sum of the volumes from all three trials:
[tex]\[ 24.10 \, ml + 23.10 \, ml + 23.70 \, ml = 70.90 \, ml \][/tex]
### Final Result:
- Volumes of [tex]\( NaOH \)[/tex] added in each trial: [tex]\([24.1, 23.1, 23.7] \, ml\)[/tex]
- Total volume of [tex]\( NaOH \)[/tex] added: [tex]\( 70.9 \, ml \)[/tex]
Thus, we have our detailed, step-by-step solution:
1. For Trial 1, the volume added is [tex]\( 24.10 \, ml \)[/tex].
2. For Trial 2, the volume added is [tex]\( 23.10 \, ml \)[/tex].
3. For Trial 3, the volume added is [tex]\( 23.70 \, ml \)[/tex].
4. The total volume of [tex]\( NaOH \)[/tex] added across all trials is [tex]\( 70.90 \, ml \)[/tex].
This concludes the comprehensive solution to the given question.
