To solve the question about the volume of [tex]\( \text{NaOH} \)[/tex] added and the concentration of [tex]\( \text{HCl} \)[/tex], we start by analyzing the burette readings and calculating the volume of [tex]\( \text{NaOH} \)[/tex] used.
1. Initial Reading: The initial burette reading is [tex]\( 0.00 \ ml \)[/tex].
2. Final Reading: The final burette reading is [tex]\( 24.10 \ ml \)[/tex].
3. Volume of [tex]\( \text{NaOH} \)[/tex] Added:
To find the volume of [tex]\( \text{NaOH} \)[/tex] added, we subtract the initial reading from the final reading:
[tex]\[
\text{Volume of NaOH added} = \text{Final reading} - \text{Initial reading} = 24.10 \ ml - 0.00 \ ml = 24.10 \ ml
\][/tex]
4. Concentration of [tex]\( \text{HCl} \)[/tex]:
The concentration of [tex]\( \text{HCl} \)[/tex] is not provided in the given data, so it is impossible to determine the exact concentration with the information available here. Therefore, the concentration of [tex]\( \text{HCl} \)[/tex] remains unknown in this setup.
Summarizing the results in the tabular form:
[tex]\[
\begin{tabular}{|l|c|c|c|l|}
\hline \multirow{2}{}{ Trial } & \multicolumn{2}{|c|}{ Burette reading } & \multirow{2}{}{ Volume $( ml )$ added $( NaOH )$} & Concentration $( M ) HCl$ \\
\cline { 2 - 5 } & Initial & Final & & \\
\hline 1 & 0.00 & 24.10 & 24.10 & \text{Unknown} \\
\hline
\end{tabular}
\][/tex]
In conclusion:
- The initial burette reading is [tex]\( 0.00 \ ml \)[/tex].
- The final burette reading is [tex]\( 24.10 \ ml \)[/tex].
- The volume of [tex]\( \text{NaOH} \)[/tex] added is [tex]\( 24.10 \ ml \)[/tex].
- The concentration of [tex]\( \text{HCl} \)[/tex] cannot be determined from the given information and remains unknown.
