Solve for [tex]\( x \)[/tex].

Since the angles are congruent, we can set their equations equal to each other.

[tex]\[
\begin{aligned}
3x + 2 & = x + 28 \\
3x - x + 2 & = 28 \\
2x + 2 & = 28 \\
2x & = 26 \\
x & = 13
\end{aligned}
\][/tex]



Answer :

To solve the equation for [tex]\( x \)[/tex], we will follow a step-by-step approach:

1. Start with the given equation:
[tex]\[ 3x + 2 = x + 28 \][/tex]

2. Isolate the [tex]\( x \)[/tex]-terms on one side. To do this, subtract [tex]\( x \)[/tex] from both sides of the equation:
[tex]\[ 3x - x + 2 = x - x + 28 \][/tex]
Simplifying this:
[tex]\[ 2x + 2 = 28 \][/tex]

3. Isolate the constant term on the other side. To do this, subtract 2 from both sides of the equation:
[tex]\[ 2x + 2 - 2 = 28 - 2 \][/tex]
Simplifying this:
[tex]\[ 2x = 26 \][/tex]

4. Solve for [tex]\( x \)[/tex] by dividing both sides by 2:
[tex]\[ x = \frac{26}{2} \][/tex]
Simplifying this division:
[tex]\[ x = 13 \][/tex]

Thus, the solution for [tex]\( x \)[/tex] is:
[tex]\[ x = 13 \][/tex]