Find the equation of a straight line cutting off an intercept of 2 from the y-axis and inclined at an angle [tex]\(\tan^{-1} \left(\frac{1}{4}\right)\)[/tex] with the x-axis.



Answer :

Sure! Let's solve this problem step by step.

1. Identify the y-Intercept (c):
The y-intercept of the line is where the line crosses the y-axis. This value is given as 2.

2. Determine the Slope (m):
The slope of a line is the tangent of the angle it makes with the x-axis. Here, the tangent of the angle is given as [tex]\(\frac{1}{4}\)[/tex].

Therefore, the slope [tex]\( m = \frac{1}{4} \)[/tex].

3. Form the Equation of the Line:
The standard form of the equation of a line in slope-intercept form is:
[tex]\[ y = mx + c \][/tex]
where [tex]\( m \)[/tex] is the slope and [tex]\( c \)[/tex] is the y-intercept.

Substitute the given values of [tex]\( m \)[/tex] and [tex]\( c \)[/tex] into this form:
[tex]\[ y = \frac{1}{4}x + 2 \][/tex]

Hence, the equation of the straight line is:
[tex]\[ y = 0.25x + 2 \][/tex]

This is the desired equation of the line that cuts off an intercept of 2 from the y-axis and is inclined at an angle such that [tex]\(\tan\)[/tex] of the angle is [tex]\(\frac{1}{4}\)[/tex] with the x-axis.