Solve the equation.

[tex]\sqrt{4x - 3} - \sqrt{x - 3} = 3[/tex]

Drag the choice or choices into the box to correctly state the solution to the equation.



Answer :

Certainly! Let's go through the solution step-by-step:

We are trying to solve the equation:

[tex]\[ \sqrt{4x - 3} - \sqrt{x - 3} = 3 \][/tex]

Step 1: Isolate one of the square roots

First, we need to isolate one of the square roots. Let's isolate [tex]\(\sqrt{4x - 3}\)[/tex]:

[tex]\[ \sqrt{4x - 3} = \sqrt{x - 3} + 3 \][/tex]

Step 2: Square both sides to eliminate the square root

Next, we square both sides of the equation in order to eliminate the square root:

[tex]\[ (\sqrt{4x - 3})^2 = (\sqrt{x - 3} + 3)^2 \][/tex]

This gives us:

[tex]\[ 4x - 3 = (x - 3) + 6\sqrt{x - 3} + 9 \][/tex]

Simplify the right-hand side of the equation:

[tex]\[ 4x - 3 = x - 3 + 6\sqrt{x - 3} + 9 \][/tex]

Combine like terms:

[tex]\[ 4x - 3 = x + 6\sqrt{x - 3} + 6 \][/tex]

Step 3: Isolate the term with the square root

Next, we need to isolate the term with the square root:

[tex]\[ 4x - x - 3 - 6 = 6\sqrt{x - 3} \][/tex]

Simplify the equation:

[tex]\[ 3x - 9 = 6\sqrt{x - 3} \][/tex]

Step 4: Square both sides again

Square both sides of the equation again to eliminate the remaining square root:

[tex]\[ (3x - 9)^2 = (6\sqrt{x - 3})^2 \][/tex]

This gives us:

[tex]\[ (3x - 9)^2 = 36(x - 3) \][/tex]

Expand the left-hand side:

[tex]\[ 9x^2 - 54x + 81 = 36x - 108 \][/tex]

Step 5: Bring all terms to one side

Move all terms to one side to set the equation to zero:

[tex]\[ 9x^2 - 54x + 81 - 36x + 108 = 0 \][/tex]

Combine like terms:

[tex]\[ 9x^2 - 90x + 189 = 0 \][/tex]

Step 6: Simplify the quadratic equation

Divide the entire equation by 9 to simplify it:

[tex]\[ x^2 - 10x + 21 = 0 \][/tex]

Step 7: Solve the quadratic equation

Now we need to solve this quadratic equation. We can factor it:

[tex]\[ (x - 3)(x - 7) = 0 \][/tex]

So, the solutions to the equation are:

[tex]\[ x = 3 \quad \text{and} \quad x = 7 \][/tex]

Step 8: Verify the solutions

We need to check whether both solutions satisfy the original equation.

For [tex]\(x = 3\)[/tex]:

[tex]\[ \sqrt{4(3) - 3} - \sqrt{3 - 3} = \sqrt{12 - 3} - \sqrt{0} = \sqrt{9} - 0 = 3 \quad \text{(which satisfies the equation)} \][/tex]

For [tex]\(x = 7\)[/tex]:

[tex]\[ \sqrt{4(7) - 3} - \sqrt{7 - 3} = \sqrt{28 - 3} - \sqrt{4} = \sqrt{25} - 2 = 5 - 2 = 3 \quad \text{(which also satisfies the equation)} \][/tex]

Therefore, the solutions to the equation are:

3 and 7