Type the correct answer in the box. Use numerals instead of words.

[tex]\[
\begin{array}{l}
-3n^2 + 147 = 0 \\
n = \pm \square
\end{array}
\][/tex]



Answer :

To solve the given equation [tex]\(-3n^2 + 147 = 0\)[/tex], follow these steps:

1. Move 147 to the other side of the equation:
[tex]\[ -3n^2 = -147 \][/tex]

2. Divide both sides by [tex]\(-3\)[/tex] to isolate [tex]\(n^2\)[/tex]:
[tex]\[ n^2 = 49 \][/tex]

3. Take the square root of both sides to solve for [tex]\(n\)[/tex]:
[tex]\[ n = \pm \sqrt{49} \][/tex]

4. Simplify the square root of 49:
[tex]\[ \sqrt{49} = 7 \][/tex]

Therefore, the solution is:
[tex]\[ n = \pm 7 \][/tex]

So, the correct answer in the box is:
[tex]\[ n = \pm 7 \][/tex]