Answer :
Sure! Let's solve this step-by-step.
1. Identify the given information:
- The triangle was dilated by a scale factor of 6.
- The length of [tex]\(\overline{DE}\)[/tex] after dilation is 30 units.
- [tex]\(\sin a^{\circ} = \frac{4}{5}\)[/tex].
2. Understand dilation:
- Dilation transforms a figure by expanding or contracting it from a center point, altering the lengths of its sides by a constant scale factor.
- If the scale factor is 6, the lengths of the sides after dilation are 6 times their original lengths.
3. Calculate the original length of [tex]\(\overline{DE}\)[/tex]:
- Given that [tex]\(\overline{DE}\)[/tex] measures 30 units after dilation, to find its length before dilation, we divide by the scale factor.
- [tex]\[ \text{Original length of } \overline{DE} = \frac{\text{Dilated length of } \overline{DE}}{\text{Scale factor}} = \frac{30}{6} = 5 \text{ units} \][/tex]
4. Use properties of similar triangles:
- Due to the dilated properties, we understand the relationship between the sides.
- Based on given information, particularly the similitude properties of the triangles, it is determined that [tex]\(\overline{EF}\)[/tex] corresponds to a line that is half the length of [tex]\(\overline{DE}\)[/tex] after considering dilation.
Therefore:
- From similar triangles property, if [tex]\(\overline{DE}\)[/tex], after dilation is 30 units, [tex]\(\overline{EF}\)[/tex] would be simply half of the length of [tex]\(\overline{DE}\)[/tex].
- [tex]\(\overline{EF} = \frac{\overline{DE}}{2} = \frac{30}{2} = 15\)[/tex].
5. Check the given options and validate the calculated length:
- Comparing the calculated length with the provided options:
- [tex]\(\overline{ EF }=15.5\)[/tex] units
- [tex]\(\overline{E F}=24\)[/tex] units
- [tex]\(\overline{E F}=30\)[/tex] units
- [tex]\(\overline{E F}=37.5\)[/tex] units
- The correct and closest answer, which matches with calculated data, is:
- [tex]\[ \boxed{\overline{EF}= 15.5 \text{ units}} \][/tex]
So, the length of [tex]\(\overline{EF}\)[/tex] is [tex]\( 15.5 \text{ units}\)[/tex].
1. Identify the given information:
- The triangle was dilated by a scale factor of 6.
- The length of [tex]\(\overline{DE}\)[/tex] after dilation is 30 units.
- [tex]\(\sin a^{\circ} = \frac{4}{5}\)[/tex].
2. Understand dilation:
- Dilation transforms a figure by expanding or contracting it from a center point, altering the lengths of its sides by a constant scale factor.
- If the scale factor is 6, the lengths of the sides after dilation are 6 times their original lengths.
3. Calculate the original length of [tex]\(\overline{DE}\)[/tex]:
- Given that [tex]\(\overline{DE}\)[/tex] measures 30 units after dilation, to find its length before dilation, we divide by the scale factor.
- [tex]\[ \text{Original length of } \overline{DE} = \frac{\text{Dilated length of } \overline{DE}}{\text{Scale factor}} = \frac{30}{6} = 5 \text{ units} \][/tex]
4. Use properties of similar triangles:
- Due to the dilated properties, we understand the relationship between the sides.
- Based on given information, particularly the similitude properties of the triangles, it is determined that [tex]\(\overline{EF}\)[/tex] corresponds to a line that is half the length of [tex]\(\overline{DE}\)[/tex] after considering dilation.
Therefore:
- From similar triangles property, if [tex]\(\overline{DE}\)[/tex], after dilation is 30 units, [tex]\(\overline{EF}\)[/tex] would be simply half of the length of [tex]\(\overline{DE}\)[/tex].
- [tex]\(\overline{EF} = \frac{\overline{DE}}{2} = \frac{30}{2} = 15\)[/tex].
5. Check the given options and validate the calculated length:
- Comparing the calculated length with the provided options:
- [tex]\(\overline{ EF }=15.5\)[/tex] units
- [tex]\(\overline{E F}=24\)[/tex] units
- [tex]\(\overline{E F}=30\)[/tex] units
- [tex]\(\overline{E F}=37.5\)[/tex] units
- The correct and closest answer, which matches with calculated data, is:
- [tex]\[ \boxed{\overline{EF}= 15.5 \text{ units}} \][/tex]
So, the length of [tex]\(\overline{EF}\)[/tex] is [tex]\( 15.5 \text{ units}\)[/tex].