The two-way table shows the number of sport utility vehicles with certain features for sale:

[tex]\[
\begin{tabular}{|c|c|c|c|}
\hline & \begin{tabular}{c}
$4-$ Wheel \\
Drive
\end{tabular} & \begin{tabular}{c}
No 4-Wheel \\
Drive
\end{tabular} & Total \\
\hline Third-Row Seats & 18 & 12 & 30 \\
\hline No Third-Row Seats & 7 & 28 & 35 \\
\hline Total & 25 & 40 & 65 \\
\hline
\end{tabular}
\][/tex]

What is the probability that a randomly selected car with no 4-wheel drive has third-row seats?

A. 0.3
B. 0.4
C. 0.7
D. 0.8



Answer :

To find the probability that a randomly selected car with no 4-wheel drive has third-row seats, follow these steps:

1. Identify the relevant data from the table:
- Number of cars with no 4-wheel drive: 40 (found in the column labeled "No 4-Wheel Drive" in the Total row).
- Number of cars with no 4-wheel drive that have third-row seats: 12 (found at the intersection of the "Third-Row Seats" row and the "No 4-Wheel Drive" column).

2. Calculate the probability:
- The probability is the ratio of the number of cars with no 4-wheel drive that have third-row seats to the total number of cars with no 4-wheel drive.
- Probability = (Number of cars with no 4-wheel drive that have third-row seats) / (Total number of cars with no 4-wheel drive).

3. Perform the division:
- Probability = 12 / 40.
- This simplifies to 0.3.

Thus, the probability that a randomly selected car with no 4-wheel drive has third-row seats is 0.3.

Therefore, the correct answer is 0.3.