Sure, let's go through the process step by step to understand how the mean and median of the fundraiser totals for the last five years compare.
1. Listing the Yearly Totals:
- Year 1: \[tex]$896
- Year 2: \$[/tex]925
- Year 3: \[tex]$880
- Year 4: \$[/tex]963
- Year 5: \[tex]$914
2. Calculate the Mean:
The mean (average) is calculated by adding all the totals together and then dividing by the number of years.
\[
\text{Mean} = \frac{896 + 925 + 880 + 963 + 914}{5} = \frac{4578}{5} = 915.6
\]
3. Calculate the Median:
To find the median, we need to arrange the totals in ascending order and then find the middle value.
Arranging in ascending order:
\[
880, \ 896, \ 914, \ 925, \ 963
\]
The median is the middle number in the ordered list:
\[
\text{Median} = 914.0
\]
4. Compare the Mean and the Median:
We now compare the mean and the median by finding the difference between them:
\[
\text{Difference} = \text{Median} - \text{Mean} = 914.0 - 915.6 = -1.6
\]
A negative difference indicates that the mean is greater than the median. Specifically:
\[
\text{The mean ( } 915.6 \text{) is \$[/tex]1.60 greater than the median ( } 914.0 \text{).}
\]
5. Conclusion:
Comparing the calculated values:
- The mean of the totals is \[tex]$915.6.
- The median of the totals is \$[/tex]914.0.
- The mean is \[tex]$1.60 greater than the median.
Thus, the correct answer is:
\[
\boxed{\text{The mean is \$[/tex]1.60 greater than the median.}}
\]
