In this problem, [tex]\(a\)[/tex], [tex]\(b\)[/tex], [tex]\(c\)[/tex], and [tex]\(d\)[/tex] are nonzero integers. If [tex]\(\frac{a}{b}\)[/tex] is added to [tex]\(x\)[/tex], the sum is [tex]\(\frac{c}{d}\)[/tex]. Which statement can be used to prove that [tex]\(x\)[/tex] must be a rational number?

A. [tex]\(x = \frac{c-a}{d-b}\)[/tex]
B. [tex]\(x = \frac{c+a}{d-b}\)[/tex]
C. [tex]\(x = \frac{cb - ad}{bd}\)[/tex]
D. [tex]\(x = \frac{cb + ad}{bd}\)[/tex]



Answer :

Let's start with the given equation:

[tex]\[ x + \frac{a}{b} = \frac{c}{d} \][/tex]

Our goal is to isolate [tex]\( x \)[/tex]. First, let's rearrange this equation to solve for [tex]\( x \)[/tex]:

[tex]\[ x = \frac{c}{d} - \frac{a}{b} \][/tex]

To subtract these fractions, we need a common denominator. The common denominator of [tex]\( \frac{c}{d} \)[/tex] and [tex]\( \frac{a}{b} \)[/tex] is [tex]\( bd \)[/tex]. Let's rewrite both fractions with this common denominator:

[tex]\[ x = \frac{c \cdot b}{d \cdot b} - \frac{a \cdot d}{b \cdot d} \][/tex]

[tex]\[ x = \frac{cb}{bd} - \frac{ad}{bd} \][/tex]

Now that both fractions have the same denominator, we can combine them into one fraction:

[tex]\[ x = \frac{cb - ad}{bd} \][/tex]

This is a single fraction where both the numerator and the denominator are products of integers, hence [tex]\( x \)[/tex] is rational because it is the ratio of two integers.

Therefore, the correct statement that shows [tex]\( x \)[/tex] must be rational is:

[tex]\[ x = \frac{cb - ad}{bd} \][/tex]

This corresponds to the third option in the given list:

[tex]\[ \boxed{\frac{cb - ad}{bd}} \][/tex]

Thus, the correct option is the third one, and it proves that [tex]\( x \)[/tex] must be a rational number.