What is the solution to the equation [tex]$6y - 2(y + 1) = 3(y - 2) + 6$[/tex]?

A. [tex]$y = -10$[/tex]
B. [tex][tex]$y = -2$[/tex][/tex]
C. [tex]$y = 2$[/tex]
D. [tex]$y = 6$[/tex]



Answer :

Let's solve the given equation step by step:

The given equation is:
[tex]\[ 6y - 2(y + 1) = 3(y - 2) + 6 \][/tex]

First, let's expand and simplify both sides.

Start by distributing the terms inside the parentheses:

[tex]\[ 6y - 2(y + 1) - (3(y - 2) + 6) \][/tex]

Expand the terms:

[tex]\[ 6y - 2y - 2 - 3y + 6 - 6 \][/tex]

Now, combine like terms:

[tex]\[ (6y - 2y - 3y) - 2 + 6 - 6 \][/tex]
[tex]\[ (6y - 5y) - 2 \][/tex]
[tex]\[ y - 2 = 0 \][/tex]

Move the constant term to the other side of the equation to isolate [tex]\( y \)[/tex]:

[tex]\[ y = 2 \][/tex]

This means the solution to the equation is:
[tex]\[ y = 2 \][/tex]

Therefore, the correct answer from the given choices is:

[tex]\[ y = 2 \][/tex]