Answer :
To solve the division [tex]\(\frac{-20}{2}\)[/tex], follow these steps:
1. Identify the numerator and the denominator. In this case, the numerator is [tex]\(-20\)[/tex] and the denominator is [tex]\(2\)[/tex].
2. Perform the division operation by dividing the numerator by the denominator. This means you divide [tex]\(-20\)[/tex] by [tex]\(2\)[/tex].
3. When you divide a negative number by a positive number, the result will be negative. Specifically:
[tex]\[ \frac{-20}{2} = -10 \][/tex]
4. To ensure the accuracy of our result, consider the properties of division:
- Division of two integers where one is negative results in a negative quotient.
- The absolute value (magnitude) of [tex]\(-20\)[/tex] divided by the absolute value of [tex]\(2\)[/tex] is [tex]\(\frac{20}{2} = 10\)[/tex].
- Combining these [tex]\(10\)[/tex] with the negative sign from the numerator gives [tex]\(-10\)[/tex].
Therefore, the final result of [tex]\(\frac{-20}{2}\)[/tex] is [tex]\(-10\)[/tex].
So,
[tex]\[ \frac{-20}{2} = -10 \][/tex]
In decimal form, the result is [tex]\(-10.0\)[/tex].
1. Identify the numerator and the denominator. In this case, the numerator is [tex]\(-20\)[/tex] and the denominator is [tex]\(2\)[/tex].
2. Perform the division operation by dividing the numerator by the denominator. This means you divide [tex]\(-20\)[/tex] by [tex]\(2\)[/tex].
3. When you divide a negative number by a positive number, the result will be negative. Specifically:
[tex]\[ \frac{-20}{2} = -10 \][/tex]
4. To ensure the accuracy of our result, consider the properties of division:
- Division of two integers where one is negative results in a negative quotient.
- The absolute value (magnitude) of [tex]\(-20\)[/tex] divided by the absolute value of [tex]\(2\)[/tex] is [tex]\(\frac{20}{2} = 10\)[/tex].
- Combining these [tex]\(10\)[/tex] with the negative sign from the numerator gives [tex]\(-10\)[/tex].
Therefore, the final result of [tex]\(\frac{-20}{2}\)[/tex] is [tex]\(-10\)[/tex].
So,
[tex]\[ \frac{-20}{2} = -10 \][/tex]
In decimal form, the result is [tex]\(-10.0\)[/tex].