Segment [tex]$AB$[/tex] falls on the line [tex]$2x - 4y = 8$[/tex]. Segment [tex][tex]$CD$[/tex][/tex] falls on the line [tex]$4x + 2y = 8$[/tex].

What is true about segments [tex]$AB$[/tex] and [tex][tex]$CD$[/tex][/tex]?

A. They are perpendicular because they have the same slope of -2.
B. They are perpendicular because they have slopes that are opposite reciprocals of -2 and [tex]$\frac{1}{2}$[/tex].
C. They are lines that lie exactly on top of one another because they have the same slope and the same [tex]$y$[/tex]-intercept.
D. They are lines that lie exactly on top of one another because they have the same slope and a different [tex][tex]$y$[/tex][/tex]-intercept.



Answer :

To determine the relationship between the segments [tex]\(AB\)[/tex] and [tex]\(CD\)[/tex] that lie on the lines [tex]\(2x - 4y = 8\)[/tex] and [tex]\(4x + 2y = 8\)[/tex] respectively, we need to analyze their slopes and intercepts.

1. Determine the Slope of Line [tex]\(2x - 4y = 8\)[/tex]:
- First, rewrite the equation in slope-intercept form [tex]\(y = mx + b\)[/tex]:
[tex]\[ 2x - 4y = 8 \implies -4y = -2x + 8 \implies y = \frac{1}{2}x - 2 \][/tex]
- The slope ([tex]\(m\)[/tex]) of this line is [tex]\(\frac{1}{2}\)[/tex].

2. Determine the Slope of Line [tex]\(4x + 2y = 8\)[/tex]:
- Rewrite the equation in slope-intercept form [tex]\(y = mx + b\)[/tex]:
[tex]\[ 4x + 2y = 8 \implies 2y = -4x + 8 \implies y = -2x + 4 \][/tex]
- The slope ([tex]\(m\)[/tex]) of this line is [tex]\(-2\)[/tex].

3. Analyzing the Slopes:
- Line [tex]\(AB\)[/tex] has a slope of [tex]\(\frac{1}{2}\)[/tex].
- Line [tex]\(CD\)[/tex] has a slope of [tex]\(-2\)[/tex].

4. Checking for Perpendicularity:
- Lines are perpendicular if their slopes are opposite reciprocals, i.e., the product of their slopes should be [tex]\(-1\)[/tex].
- The product of the slopes is:
[tex]\[ \left(\frac{1}{2}\right) \times (-2) = -1 \][/tex]
- Since the product is [tex]\(-1\)[/tex], the lines are perpendicular.

5. Checking for Coincidence:
- For the lines to be the same, they must have identical slopes and the same [tex]\(y\)[/tex]-intercept.
- The slopes of the lines are different ([tex]\(\frac{1}{2}\)[/tex] vs. [tex]\(-2\)[/tex]), hence the lines are not identical nor do they lie on top of one another.

Based on this analysis, here is the correct statement:
- They are perpendicular because they have slopes that are opposite reciprocals of [tex]\(\frac{1}{2}\)[/tex] and [tex]\(-2\)[/tex].

In conclusion, the correct statement is: "They are perpendicular because they have slopes that are opposite reciprocals of [tex]\(\frac{1}{2}\)[/tex] and [tex]\(-2\)[/tex]."