For each hour he babysits, Anderson earns \[tex]$1 more than half of Carey's hourly rate. Anderson earns \$[/tex]6 per hour. Which equation can be used to solve for Carey's hourly rate, [tex]\(c\)[/tex]?

A. [tex]\(\frac{1}{2}c + 1 = 6\)[/tex]
B. [tex]\(\frac{1}{2}c - 1 = 6\)[/tex]
C. [tex]\(\frac{1}{2}c + 6 = 1\)[/tex]
D. [tex]\(\frac{1}{2}c - 6 = 1\)[/tex]



Answer :

To determine the equation that can be used to solve for Carey's hourly rate [tex]\(c\)[/tex], let's break down the details given in the problem.

1. Let [tex]\(c\)[/tex] be Carey's hourly rate.
2. Anderson earns [tex]\(\$6\)[/tex] per hour.
3. Anderson's earnings per hour are [tex]\(\$1\)[/tex] more than half of Carey's hourly rate.

To translate this into a mathematical equation, consider the following steps:

- Half of Carey's hourly rate is represented by [tex]\(\frac{1}{2}c\)[/tex].
- Anderson earns [tex]\(\$1\)[/tex] more than this amount, so we add 1 to [tex]\(\frac{1}{2}c\)[/tex].

Thus, Anderson’s hourly earnings can be expressed as:
[tex]\[ \frac{1}{2}c + 1 \][/tex]

We know from the problem statement that Anderson actually earns [tex]\(\$6\)[/tex] per hour. Therefore, we set the equation equal to 6:
[tex]\[ \frac{1}{2} c + 1 = 6 \][/tex]

So, the correct equation to solve for Carey's hourly rate [tex]\(c\)[/tex] is:
[tex]\[ \boxed{\frac{1}{2} c + 1 = 6} \][/tex]