Answer :
To solve the rational equation
[tex]\[ \frac{x+6}{x-3} = \frac{4}{7}, \][/tex]
we will follow a step-by-step approach.
1. Cross-multiply to eliminate the fractions:
Multiply both sides of the equation by [tex]\((x - 3)\)[/tex] and 7 to get rid of the fractions.
[tex]\[ 7(x + 6) = 4(x - 3) \][/tex]
2. Distribute and simplify:
Distribute the numbers 7 and 4 on both sides of the equation.
[tex]\[ 7x + 42 = 4x - 12 \][/tex]
3. Isolate the variable [tex]\(x\)[/tex]:
To isolate [tex]\(x\)[/tex], you need to get all [tex]\(x\)[/tex] terms on one side and constants on the other. Subtract [tex]\(4x\)[/tex] from both sides.
[tex]\[ 7x - 4x + 42 = -12 \][/tex]
Simplify.
[tex]\[ 3x + 42 = -12 \][/tex]
Now, subtract 42 from both sides.
[tex]\[ 3x = -12 - 42 \][/tex]
Simplify.
[tex]\[ 3x = -54 \][/tex]
4. Solve for [tex]\(x\)[/tex]:
Divide both sides by 3.
[tex]\[ x = \frac{-54}{3} \][/tex]
Simplify.
[tex]\[ x = -18 \][/tex]
Thus, the correct solution to the given rational equation is:
[tex]\[ \boxed{x = -18} \][/tex]
Among the given choices, the correct one is:
D. [tex]\(x = -18\)[/tex]
[tex]\[ \frac{x+6}{x-3} = \frac{4}{7}, \][/tex]
we will follow a step-by-step approach.
1. Cross-multiply to eliminate the fractions:
Multiply both sides of the equation by [tex]\((x - 3)\)[/tex] and 7 to get rid of the fractions.
[tex]\[ 7(x + 6) = 4(x - 3) \][/tex]
2. Distribute and simplify:
Distribute the numbers 7 and 4 on both sides of the equation.
[tex]\[ 7x + 42 = 4x - 12 \][/tex]
3. Isolate the variable [tex]\(x\)[/tex]:
To isolate [tex]\(x\)[/tex], you need to get all [tex]\(x\)[/tex] terms on one side and constants on the other. Subtract [tex]\(4x\)[/tex] from both sides.
[tex]\[ 7x - 4x + 42 = -12 \][/tex]
Simplify.
[tex]\[ 3x + 42 = -12 \][/tex]
Now, subtract 42 from both sides.
[tex]\[ 3x = -12 - 42 \][/tex]
Simplify.
[tex]\[ 3x = -54 \][/tex]
4. Solve for [tex]\(x\)[/tex]:
Divide both sides by 3.
[tex]\[ x = \frac{-54}{3} \][/tex]
Simplify.
[tex]\[ x = -18 \][/tex]
Thus, the correct solution to the given rational equation is:
[tex]\[ \boxed{x = -18} \][/tex]
Among the given choices, the correct one is:
D. [tex]\(x = -18\)[/tex]