Which equation can be used to find the number of hours, [tex]x[/tex], it would take for Bethany and Colin to mow the lawn together?

\begin{tabular}{|c|c|c|c|}
\hline
& \begin{tabular}{c}
Rate \\
(Lawns per Hour)
\end{tabular}
& \begin{tabular}{c}
Time \\
(Hours)
\end{tabular}
& Fraction Completed \\
\hline
Bethany & [tex]$\frac{1}{4}$[/tex] & [tex]$x$[/tex] & [tex]$\frac{1}{4} x$[/tex] \\
\hline
Colin & [tex]$\frac{1}{3}$[/tex] & [tex]$x$[/tex] & [tex]$\frac{1}{3} x$[/tex] \\
\hline
\end{tabular}

A. [tex]$\frac{1}{4} x - \frac{1}{3} x = 1$[/tex]

B. [tex]$\frac{1}{4} x + \frac{1}{3} x = 1$[/tex]

C. [tex]$3 + 4 = x$[/tex]

D. [tex]$4 - 3 = x$[/tex]



Answer :

Let's solve the problem using the given rates and times.

We are given:
- Bethany can mow the lawn in 4 hours, so her rate is [tex]\( \frac{1}{4} \)[/tex] lawns per hour.
- Colin can mow the lawn in 3 hours, so his rate is [tex]\( \frac{1}{3} \)[/tex] lawns per hour.

### Step-by-Step Solution

1. Determine the combined work rate:
- Bethany's rate: [tex]\( \frac{1}{4} \)[/tex] lawns per hour.
- Colin's rate: [tex]\( \frac{1}{3} \)[/tex] lawns per hour.

Together, their combined rate is the sum of their individual rates:
[tex]\[ \text{Combined rate} = \frac{1}{4} + \frac{1}{3} \][/tex]

2. Find a common denominator and add the fractions:
[tex]\[ \frac{1}{4} + \frac{1}{3} \][/tex]
The least common multiple of 4 and 3 is 12. So, convert each rate to have a denominator of 12:
[tex]\[ \frac{1}{4} = \frac{3}{12} \quad \text{and} \quad \frac{1}{3} = \frac{4}{12} \][/tex]

Now add these fractions:
[tex]\[ \frac{3}{12} + \frac{4}{12} = \frac{7}{12} \][/tex]

Thus, their combined rate is [tex]\( \frac{7}{12} \)[/tex] lawns per hour.

3. Set up the equation for the combined work:
If [tex]\( x \)[/tex] is the number of hours needed for them to mow the lawn together, the equation becomes:
[tex]\[ \text{(Combined rate)} \times x = 1 \quad \text{(1 full lawn mowed)} \][/tex]
Substituting the combined rate [tex]\( \frac{7}{12} \)[/tex]:
[tex]\[ \frac{7}{12} x = 1 \][/tex]

4. Solve for [tex]\( x \)[/tex]:
[tex]\[ x = \frac{1}{\frac{7}{12}} = \frac{12}{7} \][/tex]

Simplify the fraction:
[tex]\[ x = \frac{12}{7} \approx 1.71428571428571 \][/tex]

Therefore, it would take approximately [tex]\( 1.714 \)[/tex] hours for Bethany and Colin to mow the lawn together.