What are the solutions of [tex]$x^2 - 4 = 0$[/tex]?

A. [tex]$x = -4$[/tex] or [tex][tex]$x = 4$[/tex][/tex]
B. [tex]$x = -2$[/tex] or [tex]$x = 2$[/tex]
C. [tex][tex]$x = 2$[/tex][/tex]
D. [tex]$x = 4$[/tex]



Answer :

To solve the equation [tex]\(x^2 - 4 = 0\)[/tex], we need to find the values of [tex]\(x\)[/tex] that make the equation true. Let's go through this step-by-step:

1. Start with the given equation:
[tex]\[ x^2 - 4 = 0 \][/tex]

2. Rewrite the equation by adding 4 to both sides:
[tex]\[ x^2 - 4 + 4 = 0 + 4 \][/tex]
Simplifying this, we get:
[tex]\[ x^2 = 4 \][/tex]

3. To solve for [tex]\(x\)[/tex], we need to take the square root of both sides. Remember that the square root of 4 has two solutions: one positive and one negative. Thus:
[tex]\[ x = \sqrt{4} \quad \text{or} \quad x = -\sqrt{4} \][/tex]

4. Simplify the square roots:
[tex]\[ x = 2 \quad \text{or} \quad x = -2 \][/tex]

Therefore, the solutions to the equation [tex]\(x^2 - 4 = 0\)[/tex] are [tex]\(x = 2\)[/tex] and [tex]\(x = -2\)[/tex].

The correct answer is:
[tex]\[ x = -2 \text{ or } x = 2 \][/tex]