Find the tangent line approximation [tex]\( T \)[/tex] to the graph of [tex]\( f \)[/tex] at the given point.

[tex]\[
\begin{array}{l}
f(x) = x^2, \quad (7, 49) \\
T(x) = \square
\end{array}
\][/tex]

Complete the table. (Round your answers to four decimal places.)

[tex]\[
\begin{array}{|c|c|c|c|c|c|}
\hline
x & 6.9 & 6.99 & 7 & 7.01 & 7.1 \\
\hline
f(x) & \square & \square & \square & \square & \square \\
\hline
T(x) & \square & \square & \square & \square & \square \\
\hline
\end{array}
\][/tex]



Answer :

To find the tangent line approximation [tex]\( T \)[/tex] to the graph of [tex]\( f \)[/tex] at the given point [tex]\((7, 49)\)[/tex], we follow these steps:

1. Find the function [tex]\( f(x) \)[/tex] and its value at [tex]\( x = 7 \)[/tex]:
[tex]\[ f(x) = x^2 \][/tex]
At [tex]\( x = 7 \)[/tex]:
[tex]\[ f(7) = 7^2 = 49 \][/tex]

2. Calculate the derivative [tex]\( f'(x) \)[/tex]:
[tex]\[ f'(x) = 2x \][/tex]
The derivative at [tex]\( x = 7 \)[/tex] is:
[tex]\[ f'(7) = 2 \times 7 = 14 \][/tex]

3. Write the equation of the tangent line:
The equation of the tangent line at point [tex]\((7, 49)\)[/tex] is given by:
[tex]\[ T(x) = f(7) + f'(7) \cdot (x - 7) \][/tex]
Substituting the values:
[tex]\[ T(x) = 49 + 14 \cdot (x - 7) \][/tex]

4. Simplify the equation of the tangent line:
[tex]\[ T(x) = 49 + 14x - 98 \][/tex]
[tex]\[ T(x) = 14x - 49 \][/tex]

So, the tangent line approximation [tex]\( T \)[/tex] is:
[tex]\[ T(x) = 14x - 49 \][/tex]

Next, we complete the table by evaluating [tex]\( f(x) \)[/tex] and [tex]\( T(x) \)[/tex] at the given points [tex]\( x = 6.9, 6.99, 7, 7.01, \)[/tex] and [tex]\( 7.1 \)[/tex] and rounding the answers to four decimal places:

1. Calculating [tex]\( f(x) \)[/tex]:
- For [tex]\( x = 6.9 \)[/tex]:
[tex]\[ f(6.9) = (6.9)^2 = 47.61 \][/tex]
- For [tex]\( x = 6.99 \)[/tex]:
[tex]\[ f(6.99) = (6.99)^2 = 48.8601 \][/tex]
- For [tex]\( x = 7 \)[/tex]:
[tex]\[ f(7) = (7)^2 = 49 \][/tex]
- For [tex]\( x = 7.01 \)[/tex]:
[tex]\[ f(7.01) = (7.01)^2 = 49.1401 \][/tex]
- For [tex]\( x = 7.1 \)[/tex]:
[tex]\[ f(7.1) = (7.1)^2 = 50.41 \][/tex]

2. Calculating [tex]\( T(x) \)[/tex]:
- For [tex]\( x = 6.9 \)[/tex]:
[tex]\[ T(6.9) = 14(6.9) - 49 = 96.6 - 49 = 47.6 \][/tex]
- For [tex]\( x = 6.99 \)[/tex]:
[tex]\[ T(6.99) = 14(6.99) - 49 = 97.86 - 49 = 48.86 \][/tex]
- For [tex]\( x = 7 \)[/tex]:
[tex]\[ T(7) = 14(7) - 49 = 98 - 49 = 49 \][/tex]
- For [tex]\( x = 7.01 \)[/tex]:
[tex]\[ T(7.01) = 14(7.01) - 49 = 98.14 - 49 = 49.14 \][/tex]
- For [tex]\( x = 7.1 \)[/tex]:
[tex]\[ T(7.1) = 14(7.1) - 49 = 99.4 - 49 = 50.4 \][/tex]

Therefore, the completed table is:

[tex]\[ \begin{array}{|c|c|c|c|c|c|} \hline x & 6.9 & 6.99 & 7 & 7.01 & 7.1 \\ \hline f(x) & 47.61 & 48.8601 & 49 & 49.1401 & 50.41 \\ \hline T(x) & 47.6 & 48.86 & 49 & 49.14 & 50.4 \\ \hline \end{array} \][/tex]