Certainly! Let's walk through the division step-by-step.
We need to divide 48 by 4.
1. Setup the division:
We write the problem in long division format:
[tex]\[
4 \longdiv {48}
\][/tex]
2. Determine how many times 4 goes into the first digit of 48:
The first digit is 4.
[tex]\[
4 \div 4 = 1
\][/tex]
So, 4 goes into 4 exactly 1 time.
3. Subtract and bring down the next digit:
- Multiply 1 by 4 and place the result under the 4.
[tex]\[
4
-4
\][/tex]
- Subtract 4 from 4, which gives 0.
Bring down the next digit, which is 8. Now, we have:
[tex]\[
08
\][/tex]
4. Determine how many times 4 goes into 8:
[tex]\[
8 \div 4 = 2
\][/tex]
So, 4 goes into 8 exactly 2 times.
5. Subtract:
- Multiply 2 by 4 and place the result under the 8.
[tex]\[
8
-8
\][/tex]
- Subtract 8 from 8, which gives 0.
6. Conclusion:
There are no more digits to bring down, and our subtraction has left us with 0.
Thus, 48 divided by 4 gives us a quotient of 12 with a remainder of 0. Therefore:
[tex]\[
48 \div 4 = 12 \text{ R } 0
\][/tex]
So, the final answer is:
[tex]\[
12 \text{ R } 0
\][/tex]
