Answered

Which of the following is an even function?

A. [tex]f(x) = (x-1)^2[/tex]

B. [tex]f(x) = 8x[/tex]

C. [tex]f(x) = x^2 - x[/tex]

D. [tex]f(x) = 7[/tex]



Answer :

To determine which of the functions are even, we need to check if each function satisfies the definition of an even function. A function [tex]\( f(x) \)[/tex] is called even if [tex]\( f(x) = f(-x) \)[/tex] for all [tex]\( x \)[/tex] in its domain.

Let's test each given function accordingly:

1. Function 1: [tex]\( f(x) = (x-1)^2 \)[/tex]
[tex]\[ f(x) = (x-1)^2 \][/tex]
To test if it is even, we need to check if [tex]\( f(x) = f(-x) \)[/tex]:
[tex]\[ f(-x) = (-x-1)^2 = (-(x+1))^2 = (x+1)^2 \neq (x-1)^2 \][/tex]
Hence, [tex]\( f(x) = (x-1)^2 \)[/tex] is not an even function.

2. Function 2: [tex]\( f(x) = 8x \)[/tex]
[tex]\[ f(x) = 8x \][/tex]
To test if it is even, we need to check if [tex]\( f(x) = f(-x) \)[/tex]:
[tex]\[ f(-x) = 8(-x) = -8x \neq 8x \][/tex]
Hence, [tex]\( f(x) = 8x \)[/tex] is not an even function.

3. Function 3: [tex]\( f(x) = x^2 - x \)[/tex]
[tex]\[ f(x) = x^2 - x \][/tex]
To test if it is even, we need to check if [tex]\( f(x) = f(-x) \)[/tex]:
[tex]\[ f(-x) = (-x)^2 - (-x) = x^2 + x \neq x^2 - x \][/tex]
Hence, [tex]\( f(x) = x^2 - x \)[/tex] is not an even function.

4. Function 4: [tex]\( f(x) = 7 \)[/tex]
[tex]\[ f(x) = 7 \][/tex]
To test if it is even, we need to check if [tex]\( f(x) = f(-x) \)[/tex]:
[tex]\[ f(-x) = 7 \][/tex]
Clearly, [tex]\( f(x) = 7 = f(-x) \)[/tex] for all [tex]\( x \)[/tex].

Hence, the only even function from the given list is:
[tex]\[ f(x) = 7 \][/tex]