11. If the density of a solution is [tex]$3.12 \, \text{g} \, \text{mL}^{-1}$[/tex], the mass of 1.5 mL of the solution in significant figures is:

A. 4.7 g
B. [tex]4680 \times 10^{-3} \, \text{g}[/tex]
C. 4.680 g
D. 46.80 g



Answer :

To find the mass of the solution given its density and volume, we can use the formula:

[tex]\[ \text{mass} = \text{density} \times \text{volume} \][/tex]

Given:
- Density of the solution, [tex]\( \rho = 3.12 \, \text{g/mL} \)[/tex]
- Volume of the solution, [tex]\( V = 1.5 \, \text{mL} \)[/tex]

Now substitute the given values into the formula:

[tex]\[ \text{mass} = 3.12 \, \text{g/mL} \times 1.5 \, \text{mL} \][/tex]

After carrying out the multiplication:

[tex]\[ \text{mass} = 4.68 \, \text{g} \][/tex]

Now we need to present the result in significant figures. Both the given density and volume have 3 significant figures (3.12) and 2 significant figures (1.5) respectively. The result should therefore also be reported to 2 significant figures because the smallest number of significant figures among the given values is 2.

Rounding 4.68 to 2 significant figures gives us:

[tex]\[ \text{mass} \approx 4.7 \, \text{g} \][/tex]

Thus, the correct answer is:

(i) 4.7 g