To find the value of the voltage supply in the given circuit with a resistor valued at [tex]\(4 \, \Omega\)[/tex] and a current of [tex]\(2.5 \, A\)[/tex] flowing through it, we can use Ohm's Law. Ohm's Law states that the voltage [tex]\(V\)[/tex] across a resistor is the product of the current [tex]\(I\)[/tex] flowing through the resistor and the resistance [tex]\(R\)[/tex] of the resistor. This can be mathematically represented as:
[tex]\[ V = R \times I \][/tex]
Given:
- Resistance ([tex]\(R\)[/tex]) = [tex]\(4 \, \Omega\)[/tex]
- Current ([tex]\(I\)[/tex]) = [tex]\(2.5 \, A\)[/tex]
Now, substituting the given values into Ohm's Law:
[tex]\[ V = 4 \, \Omega \times 2.5 \, A \][/tex]
[tex]\[ V = 10 \, V \][/tex]
Therefore, the value of the voltage supply in the circuit is [tex]\(10 \, V\)[/tex].