Answer :

To determine if the sum of the series [tex]\(\frac{1}{27} + \frac{1}{3} + \frac{1}{3}\)[/tex] equals 243, let's proceed step-by-step through the relevant calculations.

1. Adding the Series Terms:
- First, we notice that the terms in the series are [tex]\(\frac{1}{27}\)[/tex], [tex]\(\frac{1}{3}\)[/tex], and [tex]\(\frac{1}{3}\)[/tex].
- To find the sum of the series, we add these three fractions together.

2. Common Denominator:
- We need a common denominator to add these fractions. The least common multiple of 27 and 3 is 27.
- Rewrite each fraction with a denominator of 27:
[tex]\[ \frac{1}{27} + \frac{1}{3} = \frac{1}{27} + \frac{9}{27} \][/tex]
[tex]\[ \frac{1}{27} + \frac{9}{27} + \frac{9}{27} = \frac{1}{27} + \frac{9}{27} + \frac{9}{27} = \frac{1 + 9 + 9}{27} = \frac{19}{27} \][/tex]

3. Summing the Fractions:
- Adding these fractions yields:
[tex]\[ \frac{19}{27} \][/tex]

4. Decimal Representation:
- Converting [tex]\(\frac{19}{27}\)[/tex] to a decimal:
[tex]\[ \frac{19}{27} \approx 0.7037037037 \][/tex]

5. Comparison:
- We compare the sum [tex]\(0.7037037037\)[/tex] with 243.

Given the sum of the series is [tex]\(0.7037037037\)[/tex] and it does not match 243, we conclude that the sum of the given series [tex]\(\frac{1}{27} + \frac{1}{3} + \frac{1}{3}\)[/tex] is not equal to 243.