The heating or cooling of a substance is given by the equation:

[tex]\[ q = m C_{sp} \Delta T \][/tex]

Where:
[tex]\[
\begin{aligned}
q & = \text{ energy transferred as heat } \\
m & = \text{ mass } \\
C_{sp} & = \text{ specific heat } \\
\Delta T & = \text{ change in temperature }
\end{aligned}
\][/tex]

NOTE: Write [tex]\(\Delta T\)[/tex] as [tex]\(dT\)[/tex] (with no spaces) and [tex]\(C_{sp}\)[/tex] as [tex]\(C\)[/tex] for the answers below.

In order to solve for the mass, [tex]\(m\)[/tex], you must multiply both sides of the equation by the same expression:

[tex]\[ q \times \square = m C_{sp} \Delta T \times \square \][/tex]

The resulting equation is:

[tex]\[ m = \square \][/tex]



Answer :

To solve for the mass [tex]\( m \)[/tex] in the equation [tex]\( q = m C dT \)[/tex], we need to isolate [tex]\( m \)[/tex]. Here is the step-by-step solution:

1. Start with the initial equation given:
[tex]\[ q = m C dT \][/tex]

2. To isolate [tex]\( m \)[/tex], we need to divide both sides of the equation by [tex]\( C dT \)[/tex]. This can be shown as multiplying by the reciprocal of [tex]\( C dT \)[/tex]:
[tex]\[ q \times \frac{1}{C dT} = m C dT \times \frac{1}{C dT} \][/tex]

3. On the right side, the [tex]\( C dT \)[/tex] terms cancel out:
[tex]\[ q \times \frac{1}{C dT} = m \][/tex]

4. Simplifying the left side:
[tex]\[ \frac{q}{C dT} = m \][/tex]

Thus, the mass [tex]\( m \)[/tex] can be expressed as:
[tex]\[ m = \frac{q}{C dT} \][/tex]

To directly answer the specific parts of the question:
- The expression to multiply both sides of the equation by is:
[tex]\[ \boxempty = \frac{1}{C dT} \][/tex]

- The resulting equation to solve for [tex]\( m \)[/tex] is:
[tex]\[ m = \frac{q}{C dT} \][/tex]