Answer :
Certainly! Let's work through the solutions step-by-step.
Part 1: Complete the table to find the total number of shares bought by Mr. Chan.
For each month, we calculate the number of shares bought by dividing the investment amount (RM800) by the price per share.
1. January:
- Price per share = RM1.19
- Number of shares = RM800 / RM1.19 = 672.2689 ≈ 672 shares
2. February:
- Price per share = RM1.17
- Number of shares = RM800 / RM1.17 = 683.7607 ≈ 683 shares
3. March:
- Price per share = RM1.18
- Number of shares = RM800 / RM1.18 = 677.9661 ≈ 677 shares
4. April:
- Price per share = RM1.20
- Number of shares = RM800 / RM1.20 = 666.6667 ≈ 666 shares
5. May:
- Price per share = RM1.19
- Number of shares = RM800 / RM1.19 = 672.2689 ≈ 672 shares
6. June:
- Price per share = RM1.18
- Number of shares = RM800 / RM1.18 = 677.9661 ≈ 677 shares
Next, sum up the number of shares bought each month to find the total number of shares bought by Mr. Chan:
[tex]\[ \text{Total shares} = 672 + 683 + 677 + 666 + 672 + 677 = 4047 \text{ shares} \][/tex]
So, the complete table would be:
[tex]\[ \begin{array}{|c|c|c|c|c|c|c|} \hline \multicolumn{7}{|c|}{ \begin{array}{l} Complete the table to find the total number of shares bought by Mr. Chan. \end{array} } \\ \hline \multicolumn{3}{|c|}{\text{Month}} & \multicolumn{4}{|c|}{\text{Number of shares bought}} \\ \hline \multicolumn{3}{|c|}{January} & \multicolumn{4}{|c|}{672} \\ \hline \multicolumn{3}{|c|}{February} & \multicolumn{4}{|c|}{683} \\ \hline \multicolumn{3}{|c|}{March} & \multicolumn{4}{|c|}{677} \\ \hline \multicolumn{3}{|c|}{April} & \multicolumn{4}{|c|}{666} \\ \hline \multicolumn{3}{|c|}{May} & \multicolumn{4}{|c|}{672} \\ \hline \multicolumn{3}{|c|}{June} & \multicolumn{4}{|c|}{677} \\ \hline \multicolumn{4}{|c|}{\text{Total}} & \multicolumn{3}{|c|}{4047} \\ \hline \end{array} \][/tex]
Part 2: Calculate the total number of shares bought by Mrs. Loh.
Mrs. Loh invests the same amount of RM800 per month, but she buys all her shares at a constant price of RM1.19 per share.
1. Total number of shares bought by Mrs. Loh:
- Price per share = RM1.19
- Number of shares bought each month = RM800 / RM1.19 = 672.2689 shares
- She invests for 6 months, so we multiply the number of shares per month by 6:
[tex]\[ \text{Total shares} = 672.2689 \times 6 \approx 4033.6134 \text{ shares} \][/tex]
Therefore, Mrs. Loh bought approximately 4033.61 shares during the 6 months.
In summary:
- Mr. Chan bought a total of 4047 shares over 6 months.
- Mrs. Loh bought a total of approximately 4033.61 shares, given she invested at a constant price of RM1.19 per share over the same period.
Part 1: Complete the table to find the total number of shares bought by Mr. Chan.
For each month, we calculate the number of shares bought by dividing the investment amount (RM800) by the price per share.
1. January:
- Price per share = RM1.19
- Number of shares = RM800 / RM1.19 = 672.2689 ≈ 672 shares
2. February:
- Price per share = RM1.17
- Number of shares = RM800 / RM1.17 = 683.7607 ≈ 683 shares
3. March:
- Price per share = RM1.18
- Number of shares = RM800 / RM1.18 = 677.9661 ≈ 677 shares
4. April:
- Price per share = RM1.20
- Number of shares = RM800 / RM1.20 = 666.6667 ≈ 666 shares
5. May:
- Price per share = RM1.19
- Number of shares = RM800 / RM1.19 = 672.2689 ≈ 672 shares
6. June:
- Price per share = RM1.18
- Number of shares = RM800 / RM1.18 = 677.9661 ≈ 677 shares
Next, sum up the number of shares bought each month to find the total number of shares bought by Mr. Chan:
[tex]\[ \text{Total shares} = 672 + 683 + 677 + 666 + 672 + 677 = 4047 \text{ shares} \][/tex]
So, the complete table would be:
[tex]\[ \begin{array}{|c|c|c|c|c|c|c|} \hline \multicolumn{7}{|c|}{ \begin{array}{l} Complete the table to find the total number of shares bought by Mr. Chan. \end{array} } \\ \hline \multicolumn{3}{|c|}{\text{Month}} & \multicolumn{4}{|c|}{\text{Number of shares bought}} \\ \hline \multicolumn{3}{|c|}{January} & \multicolumn{4}{|c|}{672} \\ \hline \multicolumn{3}{|c|}{February} & \multicolumn{4}{|c|}{683} \\ \hline \multicolumn{3}{|c|}{March} & \multicolumn{4}{|c|}{677} \\ \hline \multicolumn{3}{|c|}{April} & \multicolumn{4}{|c|}{666} \\ \hline \multicolumn{3}{|c|}{May} & \multicolumn{4}{|c|}{672} \\ \hline \multicolumn{3}{|c|}{June} & \multicolumn{4}{|c|}{677} \\ \hline \multicolumn{4}{|c|}{\text{Total}} & \multicolumn{3}{|c|}{4047} \\ \hline \end{array} \][/tex]
Part 2: Calculate the total number of shares bought by Mrs. Loh.
Mrs. Loh invests the same amount of RM800 per month, but she buys all her shares at a constant price of RM1.19 per share.
1. Total number of shares bought by Mrs. Loh:
- Price per share = RM1.19
- Number of shares bought each month = RM800 / RM1.19 = 672.2689 shares
- She invests for 6 months, so we multiply the number of shares per month by 6:
[tex]\[ \text{Total shares} = 672.2689 \times 6 \approx 4033.6134 \text{ shares} \][/tex]
Therefore, Mrs. Loh bought approximately 4033.61 shares during the 6 months.
In summary:
- Mr. Chan bought a total of 4047 shares over 6 months.
- Mrs. Loh bought a total of approximately 4033.61 shares, given she invested at a constant price of RM1.19 per share over the same period.