Answer :
To determine the dimensions of the original photo, let's follow these steps:
1. Identify the dimensions of the enlarged photo:
- Width: 24 inches
- Height: 32 inches
2. Understand the given dilation factor, which in this case is 4. This means the enlarged photo dimensions are 4 times the dimensions of the original photo.
3. To find the dimensions of the original photo, we need to divide the dimensions of the enlarged photo by the dilation factor.
- Original Width = Enlarged Width ÷ Dilation Factor
[tex]\[ \text{Original Width} = \frac{24 \text{ inches}}{4} = 6 \text{ inches} \][/tex]
- Original Height = Enlarged Height ÷ Dilation Factor
[tex]\[ \text{Original Height} = \frac{32 \text{ inches}}{4} = 8 \text{ inches} \][/tex]
Therefore, the dimensions of the original photo are [tex]\( 6 \times 8 \)[/tex] inches.
So, the correct answer is:
[tex]\[ 6 \times 8 \][/tex]
1. Identify the dimensions of the enlarged photo:
- Width: 24 inches
- Height: 32 inches
2. Understand the given dilation factor, which in this case is 4. This means the enlarged photo dimensions are 4 times the dimensions of the original photo.
3. To find the dimensions of the original photo, we need to divide the dimensions of the enlarged photo by the dilation factor.
- Original Width = Enlarged Width ÷ Dilation Factor
[tex]\[ \text{Original Width} = \frac{24 \text{ inches}}{4} = 6 \text{ inches} \][/tex]
- Original Height = Enlarged Height ÷ Dilation Factor
[tex]\[ \text{Original Height} = \frac{32 \text{ inches}}{4} = 8 \text{ inches} \][/tex]
Therefore, the dimensions of the original photo are [tex]\( 6 \times 8 \)[/tex] inches.
So, the correct answer is:
[tex]\[ 6 \times 8 \][/tex]