Sylvia enlarged a photo to make a [tex]$24 \times 32$[/tex] inch poster using the dilation [tex]D_{ Q , 4}[/tex]. What are the dimensions, in inches, of the original photo?

A. [tex]3 \times 8[/tex]
B. [tex]6 \times 8[/tex]
C. [tex]12 \times 16[/tex]
D. [tex]18 \times 24[/tex]



Answer :

To determine the dimensions of the original photo, let's follow these steps:

1. Identify the dimensions of the enlarged photo:
- Width: 24 inches
- Height: 32 inches

2. Understand the given dilation factor, which in this case is 4. This means the enlarged photo dimensions are 4 times the dimensions of the original photo.

3. To find the dimensions of the original photo, we need to divide the dimensions of the enlarged photo by the dilation factor.

- Original Width = Enlarged Width ÷ Dilation Factor
[tex]\[ \text{Original Width} = \frac{24 \text{ inches}}{4} = 6 \text{ inches} \][/tex]

- Original Height = Enlarged Height ÷ Dilation Factor
[tex]\[ \text{Original Height} = \frac{32 \text{ inches}}{4} = 8 \text{ inches} \][/tex]

Therefore, the dimensions of the original photo are [tex]\( 6 \times 8 \)[/tex] inches.

So, the correct answer is:
[tex]\[ 6 \times 8 \][/tex]