Answer :
To solve this problem, let's proceed step by step.
1. Initial Mass of Zinc Strip:
- This was given as 2.50 g.
2. Final Mass of the System:
- This was measured to be 3.37 g after the reaction and drying.
3. Mass of Silver Deposited:
- To find the mass of silver deposited on the zinc strip, we need to subtract the initial mass of the zinc strip from the final mass of the system.
- Final Mass of System = 3.37 g
- Initial Mass of Zinc = 2.50 g
- Mass of Silver Deposited = Final Mass of System - Initial Mass of Zinc
- This calculates to 3.37 g - 2.50 g = 0.87 g
4. Mass of Zinc Remaining:
- Since the problem doesn't mention any zinc being dissolved and removed from the strip, we will assume that the mass of zinc remains the same.
- The mass of zinc remaining is the initial mass of the zinc strip: 2.50 g.
Therefore, the mass of silver (Ag) deposited on the strip is 0.87 g, and the mass of zinc (Zn) remaining is 2.50 g.
1. Initial Mass of Zinc Strip:
- This was given as 2.50 g.
2. Final Mass of the System:
- This was measured to be 3.37 g after the reaction and drying.
3. Mass of Silver Deposited:
- To find the mass of silver deposited on the zinc strip, we need to subtract the initial mass of the zinc strip from the final mass of the system.
- Final Mass of System = 3.37 g
- Initial Mass of Zinc = 2.50 g
- Mass of Silver Deposited = Final Mass of System - Initial Mass of Zinc
- This calculates to 3.37 g - 2.50 g = 0.87 g
4. Mass of Zinc Remaining:
- Since the problem doesn't mention any zinc being dissolved and removed from the strip, we will assume that the mass of zinc remains the same.
- The mass of zinc remaining is the initial mass of the zinc strip: 2.50 g.
Therefore, the mass of silver (Ag) deposited on the strip is 0.87 g, and the mass of zinc (Zn) remaining is 2.50 g.