What is the horizontal acceleration of a ball that is launched horizontally with a velocity of [tex]$5.6 \, \text{m/s}$[/tex]?

A. [tex]-9.8 \, \text{m/s}^2[/tex]
B. [tex]0 \, \text{m/s}^2[/tex]
C. [tex]5.6 \, \text{m/s}^2[/tex]
D. [tex]9.8 \, \text{m/s}^2[/tex]



Answer :

To determine the horizontal acceleration of a ball that is launched horizontally with a velocity of [tex]\(5.6 \, \text{m/s}\)[/tex], let's consider the factors involved in such motion.

When a ball is launched horizontally:

1. Velocity: The initial velocity of the ball is given as [tex]\(5.6 \, \text{m/s}\)[/tex] in the horizontal direction.

2. Horizontal Acceleration: In the absence of external forces such as friction or air resistance (assuming ideal conditions), the only force acting on the ball is gravity. However, gravity acts vertically downward and does not affect the horizontal motion.

Since gravity only causes vertical acceleration, the horizontal acceleration remains unaffected by gravity. There are no other horizontal forces acting on the ball in ideal conditions. Hence, the horizontal acceleration is due to no external horizontal force.

Therefore, the horizontal acceleration of the ball is:

[tex]\[ \boxed{0 \, \text{m/s}^2} \][/tex]

In conclusion, the horizontal acceleration of a ball launched horizontally is [tex]\(0 \, \text{m/s}^2\)[/tex].