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What value of [tex]p[/tex] makes the equation true?
[tex]
\begin{array}{l}
-3p + \frac{1}{8} = -\frac{1}{4} \\
p = \square
\end{array}
[/tex]



Answer :

To solve for the value of [tex]\( p \)[/tex] that makes the equation true, follow these steps:

1. Start with the given equation:
[tex]\[ -3p + \frac{1}{8} = -\frac{1}{4} \][/tex]

2. Isolate the term with [tex]\( p \)[/tex] by subtracting [tex]\(\frac{1}{8}\)[/tex] from both sides of the equation:
[tex]\[ -3p = -\frac{1}{4} - \frac{1}{8} \][/tex]

3. Simplify the right-hand side by finding a common denominator. The common denominator for [tex]\(\frac{1}{4}\)[/tex] and [tex]\(\frac{1}{8}\)[/tex] is 8.

Convert [tex]\(-\frac{1}{4}\)[/tex] to [tex]\(-\frac{2}{8}\)[/tex]:
[tex]\[ -\frac{1}{4} = -\frac{2}{8} \][/tex]

4. Subtract [tex]\(\frac{1}{8}\)[/tex] from [tex]\(-\frac{2}{8}\)[/tex]:
[tex]\[ -\frac{2}{8} - \frac{1}{8} = -\frac{3}{8} \][/tex]

5. Now, the equation is:
[tex]\[ -3p = -\frac{3}{8} \][/tex]

6. Solve for [tex]\( p \)[/tex] by dividing both sides of the equation by [tex]\(-3\)[/tex]:
[tex]\[ p = \frac{-\frac{3}{8}}{-3} \][/tex]

7. Simplify the fraction:
[tex]\[ p = \frac{\frac{3}{8}}{3} \][/tex]
[tex]\[ p = \frac{3}{8} \times \frac{1}{3} \][/tex]
[tex]\[ p = \frac{3}{24} \][/tex]
[tex]\[ p = \frac{1}{8} \][/tex]

Therefore, the value of [tex]\( p \)[/tex] that makes the equation true is:
[tex]\[ p = \boxed{\frac{1}{8}} \][/tex]