Let's determine the systematic names of the provided organic molecules.
### Molecule 1: ClCC=C(Cl)Cl
1. Identify the longest carbon chain: The longest continuous chain of carbons is 4 carbons long (butene).
2. Identify the functional groups and substituents:
- There are three chlorine atoms.
- Two double bonds are present in the chain.
3. Number the carbon chain: Number the chain such that the double bond and the substituents get the lowest possible numbers.
- Numbering from the left: C1 has a Cl, C2 has a double bond, C3 has another Cl, and C4 has the third Cl.
Thus, the systematic name for this molecule is 2,3,4-trichlorobut-1-ene.
### Molecule 2: CC(C)=CC(Cl)Cl
1. Identify the longest carbon chain: The longest chain includes the double bond and is 4 carbons long (butene).
2. Identify the functional groups and substituents:
- One chlorine substituent.
- Two methyl groups at C2.
3. Number the carbon chain: Number the chain such that the double bond and substituents get the lowest possible numbers.
- Numbering from the left: On C2, we have two methyl groups and C3 has a chlorine group.
Thus, the systematic name for this molecule is 3-chloro-2,3-dimethylbut-1-ene.
### Molecule 3: CCC=C(C)C
1. Identify the longest carbon chain: The longest continuous chain of carbons is 5 carbons long (pentene).
2. Identify the functional groups and substituents:
- There is a methyl group attached to the chain.
3. Number the carbon chain: Number the chain such that the double bond gets the lowest possible number and the substituents are correctly located.
- Counting from left to right, the double bond starts at C2.
- The methyl group is on C3.
Thus, the systematic name for this molecule is 3-methylpent-1-ene.
### Summary:
| Structure | Name |
|---|---|
| ClCC=C(Cl)Cl | 2,3,4-trichlorobut-1-ene |
| CC(C)=CC(Cl)Cl | 3-chloro-2,3-dimethylbut-1-ene |
| CCC=C(C)C | 3-methylpent-1-ene |
