A ratio of two numbers is equal to 3:8 and the smaller number is 12.

1. Write the antecedent and consequent in the given ratio.
2. Consider the greater number as [tex]\( x \)[/tex] and make an equation.
3. Solve the equation and find the greater number.



Answer :

Sure, let's solve this step-by-step.

#### (1) Write the antecedent and consequent in the given ratio.
The given ratio is 3:8.

- The antecedent (the first term) is 3.
- The consequent (the second term) is 8.

So, the ratio is 3:8, where:
- Antecedent = 3
- Consequent = 8

#### (ii) Consider the greater number as [tex]\( x \)[/tex] and make an equation.

We are given:
- Ratio of the two numbers = 3:8
- Smaller number = 12

Let's consider the greater number to be [tex]\( x \)[/tex].

According to the given ratio, the ratio of the smaller number to the greater number should be equal to the given ratio 3:8. This translates into the equation:

[tex]\[ \frac{\text{smaller number}}{\text{greater number}} = \frac{\text{antecedent}}{\text{consequent}} \][/tex]

Substitute the values:

[tex]\[ \frac{12}{x} = \frac{3}{8} \][/tex]

#### (iii) Solve the equation to find the greater number.

To solve for [tex]\( x \)[/tex], we'll cross-multiply the terms:

[tex]\[ 12 \cdot 8 = 3 \cdot x \][/tex]

[tex]\[ 96 = 3x \][/tex]

Now, isolate [tex]\( x \)[/tex] by dividing both sides by 3:

[tex]\[ x = \frac{96}{3} \][/tex]

[tex]\[ x = 32 \][/tex]

So, the greater number is [tex]\( 32 \)[/tex].

### Summary:
1. The antecedent is 3 and the consequent is 8.
2. The equation formed is [tex]\(\frac{12}{x} = \frac{3}{8}\)[/tex].
3. The greater number is 32.