Answer :
To find the quotient of the polynomial [tex]\(\frac{b^3 + 4b^2 - 3b + 128}{b + 7}\)[/tex], we will perform polynomial long division. Here is the step-by-step solution:
1. Divide the leading term of the numerator by the leading term of the divisor:
The leading term of the numerator is [tex]\(b^3\)[/tex], and the leading term of the divisor is [tex]\(b\)[/tex].
[tex]\[ \frac{b^3}{b} = b^2 \][/tex]
So, [tex]\(b^2\)[/tex] is the first term of the quotient.
2. Multiply the entire divisor by this term:
[tex]\[ b^2 \cdot (b + 7) = b^3 + 7b^2 \][/tex]
3. Subtract this from the original polynomial:
[tex]\[ (b^3 + 4b^2 - 3b + 128) - (b^3 + 7b^2) = (4b^2 - 7b^2) + (-3b) + 128 = -3b^2 - 3b + 128 \][/tex]
4. Repeat the process for the new polynomial [tex]\(-3b^2 - 3b + 128\)[/tex]:
Divide the leading term [tex]\(-3b^2\)[/tex] by [tex]\(b\)[/tex]:
[tex]\[ \frac{-3b^2}{b} = -3b \][/tex]
So, [tex]\(-3b\)[/tex] is the next term of the quotient.
5. Multiply the entire divisor by this term:
[tex]\[ -3b \cdot (b + 7) = -3b^2 - 21b \][/tex]
6. Subtract this from the polynomial:
[tex]\[ (-3b^2 - 3b + 128) - (-3b^2 - 21b) = -3b - (-21b) + 128 = 18b + 128 \][/tex]
7. Repeat the process for the new polynomial [tex]\(18b + 128\)[/tex]:
Divide the leading term [tex]\(18b\)[/tex] by [tex]\(b\)[/tex]:
[tex]\[ \frac{18b}{b} = 18 \][/tex]
So, [tex]\(18\)[/tex] is the next term of the quotient.
8. Multiply the entire divisor by this term:
[tex]\[ 18 \cdot (b + 7) = 18b + 126 \][/tex]
9. Subtract this from the polynomial:
[tex]\[ (18b + 128) - (18b + 126) = 128 - 126 = 2 \][/tex]
So, the quotient is [tex]\(b^2 - 3b + 18\)[/tex] and the remainder is [tex]\(2\)[/tex].
Therefore, the answer is:
B. [tex]\(b^2 - 3b + 18\)[/tex].
There is no remainder option in the choices, but for reference, the remainder is indeed 2 if you were to fully complete the division. The correct answer for the quotient alone is B.
1. Divide the leading term of the numerator by the leading term of the divisor:
The leading term of the numerator is [tex]\(b^3\)[/tex], and the leading term of the divisor is [tex]\(b\)[/tex].
[tex]\[ \frac{b^3}{b} = b^2 \][/tex]
So, [tex]\(b^2\)[/tex] is the first term of the quotient.
2. Multiply the entire divisor by this term:
[tex]\[ b^2 \cdot (b + 7) = b^3 + 7b^2 \][/tex]
3. Subtract this from the original polynomial:
[tex]\[ (b^3 + 4b^2 - 3b + 128) - (b^3 + 7b^2) = (4b^2 - 7b^2) + (-3b) + 128 = -3b^2 - 3b + 128 \][/tex]
4. Repeat the process for the new polynomial [tex]\(-3b^2 - 3b + 128\)[/tex]:
Divide the leading term [tex]\(-3b^2\)[/tex] by [tex]\(b\)[/tex]:
[tex]\[ \frac{-3b^2}{b} = -3b \][/tex]
So, [tex]\(-3b\)[/tex] is the next term of the quotient.
5. Multiply the entire divisor by this term:
[tex]\[ -3b \cdot (b + 7) = -3b^2 - 21b \][/tex]
6. Subtract this from the polynomial:
[tex]\[ (-3b^2 - 3b + 128) - (-3b^2 - 21b) = -3b - (-21b) + 128 = 18b + 128 \][/tex]
7. Repeat the process for the new polynomial [tex]\(18b + 128\)[/tex]:
Divide the leading term [tex]\(18b\)[/tex] by [tex]\(b\)[/tex]:
[tex]\[ \frac{18b}{b} = 18 \][/tex]
So, [tex]\(18\)[/tex] is the next term of the quotient.
8. Multiply the entire divisor by this term:
[tex]\[ 18 \cdot (b + 7) = 18b + 126 \][/tex]
9. Subtract this from the polynomial:
[tex]\[ (18b + 128) - (18b + 126) = 128 - 126 = 2 \][/tex]
So, the quotient is [tex]\(b^2 - 3b + 18\)[/tex] and the remainder is [tex]\(2\)[/tex].
Therefore, the answer is:
B. [tex]\(b^2 - 3b + 18\)[/tex].
There is no remainder option in the choices, but for reference, the remainder is indeed 2 if you were to fully complete the division. The correct answer for the quotient alone is B.