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An object moves from point A to point B to point C, then back to point B and then
point C in 20 minutes, travelling along the line shown in the diagram below. A Is at 0km, b is at 5km and C is at 9km
1. Calculate the total distance moved by the object in 20 minutes.
2. Calculate the displacement of the object in 20 minutes.
3. Calculate the average speed of the object in 20 minutes, in km h ^-1
4. Calculate the average velocity of the object in 20 minutes, in km h ^-1

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Answer :

tosinjegede399

Explanation:

Let's break it down step by step:

1. Total distance moved:

A to B = 5 km

B to C = 4 km (since C is 9 km and B is 5 km)

C to B = 4 km (back to B)

B to C = 4 km (again to C)

Total distance = 5 + 4 + 4 + 4 = 17 km

1. Displacement:

Since the object ends up at point C, which is 9 km from the starting point A, the displacement is:

Displacement = 9 km

1. Average speed:

Total distance = 17 km

Time = 20 minutes = 1/3 hour (convert minutes to hours)

Average speed = Total distance / Time = 17 km / (1/3) h = 51 km/h

1. Average velocity:

Displacement = 9 km

Time = 20 minutes = 1/3 hour

Average velocity = Displacement / Time = 9 km / (1/3) h = 27 km/h

Note that average velocity is different from average speed because it takes into account the direction of motion. In this case, the object ends up at a different point from where it started, so the average velocity is lower than the average speed.

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