Modeling Real Life

You consider buying a phone from one of two cell phone carriers. The table shows the total costs (in dollars) of the phone and service for different numbers of months at Carrier A. The total cost [tex]y[/tex] (in dollars) of the phone and [tex]x[/tex] months of service at Carrier B is represented by the equation [tex]y = 55x + 300[/tex].

Questions:
1. Which carrier charges less per month?
2. After how many months of service are the total costs the same?

Example 2



Answer :

Let's analyze and compare the two carriers based on the provided information.

### Carrier A
We are given a table with the total costs for Carrier A over different months. To determine the monthly cost and the initial cost (intercept), we can use the given data points.

| Months (x) | Total Cost (y) |
|------------|----------------|
| 1 | 70 |
| 2 | 115 |
| 3 | 160 |
| 4 | 205 |
| 5 | 250 |

From the table, we can see:
- At 1 month: the total cost is 70 dollars.
- At 2 months: the total cost is 115 dollars.
- At 3 months: the total cost is 160 dollars.
- At 4 months: the total cost is 205 dollars.
- At 5 months: the total cost is 250 dollars.

By comparing the costs for consecutive months:
[tex]\[ \text{Cost difference between any two consecutive months} = \$115 - \$70 = \$45 \][/tex]

Thus, the cost per month (slope) for Carrier A is [tex]$45. Now, to find the initial cost (intercept) for Carrier A, we can use the first data point (1 month, 70 dollars): \[ \text{Initial cost} = 70 - 45 \times 1 = 25 \] So, the equation for the total cost \( y \) of the phone and \( x \) months of service at Carrier A is: \[ y = 45x + 25 \] ### Carrier B The total cost \( y \) of the phone and \( x \) months of service at Carrier B is given by the equation: \[ y = 55x + 300 \] ### Comparing Monthly Costs - Carrier A: \( y = 45x + 25 \) (slope is 45) - Carrier B: \( y = 55x + 300 \) (slope is 55) The slope represents the monthly cost for each carrier. Comparing the slopes, Carrier A charges \( \$[/tex]45 \) per month, while Carrier B charges [tex]\( \$55 \)[/tex] per month. Therefore, Carrier A charges less per month.

### Finding the Break-Even Point
To find the point where the total costs are the same for both carriers, we set the two equations equal to each other:
[tex]\[ 45x + 25 = 55x + 300 \][/tex]

Solving for [tex]\( x \)[/tex]:
[tex]\[ 45x + 25 = 55x + 300 \][/tex]
[tex]\[ 25 - 300 = 55x - 45x \][/tex]
[tex]\[ -275 = 10x \][/tex]
[tex]\[ x = \frac{-275}{10} = -27.5 \][/tex]

Therefore, the total costs for both carriers would be the same after [tex]\(-27.5\)[/tex] months of service. This negative value indicates that, in practical terms, the two carriers will never have the same total cost within the context of real-world months of service.