Answer :
Sure! Let's go through each part of the question step-by-step.
### 1.1.1 Write Down a Formula to Represent Chloe's Total Expenses
Chloe incurs a fixed cost of R500 for renting the stall, and it costs her R5 to make each tortilla. If we let [tex]\( n \)[/tex] represent the number of tortillas sold, the total expenses [tex]\( E \)[/tex] can be expressed as:
[tex]\[ E = 500 + 5n \][/tex]
### 1.1.2 Draw Up a Table to Represent Chloe's Expenses
We calculate the expenses based on the formula [tex]\( E = 500 + 5n \)[/tex] for the provided number of tortillas ([tex]\( n \)[/tex]).
[tex]\[ \begin{array}{|l|l|} \hline \text{Number of tortillas} & \text{Total Expenses (R)} \\ \hline 0 & 500 \\ 50 & 750 \\ 100 & 1000 \\ 150 & 1250 \\ 200 & 1500 \\ 250 & 1750 \\ \hline \end{array} \][/tex]
### 1.1.3 Draw Line Graphs of Chloe's Total Income and Expenses
For the table values:
- Income: [tex]\( I = 15n \)[/tex]
- Expenses: [tex]\( E = 500 + 5n \)[/tex]
When converted into tabular format:
[tex]\[ \begin{array}{|l|l|l|} \hline \text{Number of tortillas} & \text{Total Income (R)} & \text{Total Expenses (R)} \\ \hline 0 & 0 & 500 \\ 50 & 750 & 750 \\ 100 & 1500 & 1000 \\ 150 & 2250 & 1250 \\ 200 & 3000 & 1500 \\ 250 & 3750 & 1750 \\ \hline \end{array} \][/tex]
Graphically, you will plot:
- Income line: [tex]\( (0, 0), (50, 750), (100, 1500), (150, 2250), (200, 3000), (250, 3750) \)[/tex]
- Expenses line: [tex]\( (0, 500), (50, 750), (100, 1000), (150, 1250), (200, 1500), (250, 1750) \)[/tex]
### 1.1.4 Determine the Minimum Number of Tortillas to Break Even
To find the break-even point, we need to determine when total income equals total expenses. From the table, we observe:
- At [tex]\( n = 50 \)[/tex]:
- Income: [tex]\( R750 \)[/tex]
- Expenses: [tex]\( R750 \)[/tex]
Therefore, the minimum number of tortillas Chloe must sell to break even is [tex]\( \boxed{50} \)[/tex]. This is the point at which her income equals her expenses (R750).
### 1.1.1 Write Down a Formula to Represent Chloe's Total Expenses
Chloe incurs a fixed cost of R500 for renting the stall, and it costs her R5 to make each tortilla. If we let [tex]\( n \)[/tex] represent the number of tortillas sold, the total expenses [tex]\( E \)[/tex] can be expressed as:
[tex]\[ E = 500 + 5n \][/tex]
### 1.1.2 Draw Up a Table to Represent Chloe's Expenses
We calculate the expenses based on the formula [tex]\( E = 500 + 5n \)[/tex] for the provided number of tortillas ([tex]\( n \)[/tex]).
[tex]\[ \begin{array}{|l|l|} \hline \text{Number of tortillas} & \text{Total Expenses (R)} \\ \hline 0 & 500 \\ 50 & 750 \\ 100 & 1000 \\ 150 & 1250 \\ 200 & 1500 \\ 250 & 1750 \\ \hline \end{array} \][/tex]
### 1.1.3 Draw Line Graphs of Chloe's Total Income and Expenses
For the table values:
- Income: [tex]\( I = 15n \)[/tex]
- Expenses: [tex]\( E = 500 + 5n \)[/tex]
When converted into tabular format:
[tex]\[ \begin{array}{|l|l|l|} \hline \text{Number of tortillas} & \text{Total Income (R)} & \text{Total Expenses (R)} \\ \hline 0 & 0 & 500 \\ 50 & 750 & 750 \\ 100 & 1500 & 1000 \\ 150 & 2250 & 1250 \\ 200 & 3000 & 1500 \\ 250 & 3750 & 1750 \\ \hline \end{array} \][/tex]
Graphically, you will plot:
- Income line: [tex]\( (0, 0), (50, 750), (100, 1500), (150, 2250), (200, 3000), (250, 3750) \)[/tex]
- Expenses line: [tex]\( (0, 500), (50, 750), (100, 1000), (150, 1250), (200, 1500), (250, 1750) \)[/tex]
### 1.1.4 Determine the Minimum Number of Tortillas to Break Even
To find the break-even point, we need to determine when total income equals total expenses. From the table, we observe:
- At [tex]\( n = 50 \)[/tex]:
- Income: [tex]\( R750 \)[/tex]
- Expenses: [tex]\( R750 \)[/tex]
Therefore, the minimum number of tortillas Chloe must sell to break even is [tex]\( \boxed{50} \)[/tex]. This is the point at which her income equals her expenses (R750).