tay0309
Answered

The water released 1318 J and the
calorimeter released 43 J of energy. The
energy moved into a 45.3 g sample of
unknown material, initially at 18.0 °C and
came to equilibrium with the calorimeter at
91.2 °C.
What is the heat change for the unknown
material?
qunknown = [?] J
[?] J
Enter either a + or - sign AND the magnitude.

The water released 1318 J and thecalorimeter released 43 J of energy Theenergy moved into a 453 g sample ofunknown material initially at 180 C andcame to equili class=


Answer :

Answer:

+1361 J

Explanation:

The water and the calorimeter released a combined total of energy into an unknown material. The energy released by the water is 1318 J, and the energy released by the calorimeter is 43 J, combining to 1361 J.

Given that this energy was absorbed by the unknown material, causing its temperature to rise, the heat change for the unknown material would be positive.