### PART 3: TEST
1. Name 2 properties (characteristics) of gases. (2 points)
1. Gases have no fixed shape or volume. They take the shape and volume of their container.
2. Gases are highly compressible because the particles are far apart and can be brought closer together.
2. Explain the following warning on an aerosol spray can: "Do not expose to heat or high temperature". (2 points)
Gases inside an aerosol can are under pressure. When exposed to heat or high temperatures, the gas molecules gain kinetic energy and move faster, causing the pressure inside the can to increase. If the temperature gets high enough, the increased pressure can cause the can to burst or explode, posing a danger.
3. When filling a container with gas particles and it is full, what happens if you try to force more particles into the container. (2 points)
If you try to force more gas particles into a full container, the pressure inside the container will increase. This is because the gas particles will collide more frequently with the walls of the container, resulting in increased pressure.
What would the volume be at this pressure when the pressure was 110 kPa and the volume was 34.5 cm³ (1st set of results)
Given values:
- Initial pressure, [tex]\( p_1 = 110 \ \text{kPa} \)[/tex]
- Initial volume, [tex]\( V_1 = 34.5 \ \text{cm}^3 \)[/tex]
- Final pressure, [tex]\( p_2 = 230 \ \text{kPa} \)[/tex]
We use the equation [tex]\( p_1V_1 = p_2V_2 \)[/tex].
To find the new volume [tex]\( V_2 \)[/tex]:
[tex]\[ V_2 = \frac{p_1 \cdot V_1}{p_2} \][/tex]
Substitute the given values:
[tex]\[ V_2 = \frac{110 \ \text{kPa} \cdot 34.5 \ \text{cm}^3}{230 \ \text{kPa}} \][/tex]
The new volume [tex]\( V_2 \)[/tex] is:
[tex]\[ V_2 = 16.5 \ \text{cm}^3 \][/tex]
So, the new volume at 230 kPa is [tex]\( 16.5 \ \text{cm}^3 \)[/tex].
TOTAL: 10 points
