Based on the synthesis reaction, what would the product of the reaction be?

[tex]\[ \text{NaPO}_3 + \text{CuO} \rightarrow ? \][/tex]

A. [tex]\(\text{NaO} + \text{CuPO}_3\)[/tex]

B. [tex]\(\text{Na} + \text{P} + \text{Cu} + \text{O}_4\)[/tex]

C. [tex]\(\text{NaCuPO}_4\)[/tex]

D. [tex]\(\text{NaCu} + \text{PO}_4\)[/tex]



Answer :

In order to determine the product of the synthesis reaction [tex]\( NaPO_3 + CuO \rightarrow \)[/tex], we will analyze each possible option given and apply our chemistry knowledge, specifically regarding the behavior of these reactants.

A synthesis reaction involves combining two or more simple substances to form a more complex product. Let's analyze the reactants separately:
- [tex]\( NaPO_3 \)[/tex] is sodium metaphosphate.
- [tex]\( CuO \)[/tex] is copper(II) oxide.

### Analysis of Options:
1. [tex]\( NaO + CuPO_3 \)[/tex]
- Sodium monoxide ([tex]\( NaO \)[/tex]) is not a common compound. Furthermore, this option splits the phosphate group, which is unusual for a synthesis reaction of this type. This option is unlikely.

2. [tex]\( Na + P + Cu + O_4 \)[/tex]
- This implies that all component elements remain in their elemental form or are loosely connected, which does not correspond to a typical synthesis reaction. This is a highly improbable product for synthesizing a compound.

3. [tex]\( NaCuPO_4 \)[/tex]
- This represents a single compound that includes all the elements from the reactants in a balanced and chemically plausible configuration. The phosphate group remains intact, and sodium and copper are included in the final product, which aligns with typical synthesis outcomes. This is a strong candidate.

4. [tex]\( NaCu + PO_4 \)[/tex]
- This separates sodium and copper from the phosphate group into distinct entities. Such separation isn't typical for synthesis reactions where a more stable compound is usually formed. Thus, this option is unlikely.

### Conclusion:
Considering the typical patterns of synthesis reactions and the plausibility of the compounds, the most likely product from the reaction is:

[tex]\[ NaCuPO_4 \][/tex]

Thus, the correct answer is:
[tex]\[ \boxed{NaCuPO_4} \][/tex]