Certainly! Let's solve the division problem [tex]\( 606 \div 49 \)[/tex].
### Step-by-Step Solution:
#### Step 1: Set Up the Long Division
We need to divide [tex]\( 606 \)[/tex] by [tex]\( 49 \)[/tex]. Here, [tex]\( 606 \)[/tex] is the dividend, and [tex]\( 49 \)[/tex] is the divisor.
#### Step 2: Determine How Many Times 49 Goes Into 606
First, we identify how many times [tex]\( 49 \)[/tex] can go into the most significant part of [tex]\( 606 \)[/tex] that it can divide into. So, let's see how [tex]\( 49 \)[/tex] fits into the digits of [tex]\( 606 \)[/tex]:
- [tex]\( 49 \)[/tex] into [tex]\( 60 \)[/tex] (since [tex]\( 49 \)[/tex] doesn’t fit into the first digit [tex]\( 6 \)[/tex]) fits [tex]\( 1 \)[/tex] time because [tex]\( 49 \times1= 49 \)[/tex].
Write down [tex]\( 1 \)[/tex] above the dividend line putting it above the last digit of the section we're dividing ([tex]\( 60 \)[/tex]).
#### Step 3: Subtract and Bring Down the Next Digit
Subtract [tex]\( 49 \)[/tex] from [tex]\( 60 \)[/tex]:
[tex]\[ 60 - 49 = 11 \][/tex]
Now, bring down the next digit, which is [tex]\( 6 \)[/tex], resulting in [tex]\( 116 \)[/tex].
#### Step 4: Determine How Many Times 49 Goes Into 116
Next, check how many times [tex]\( 49 \)[/tex] goes into [tex]\( 116 \)[/tex]:
- [tex]\( 49 \)[/tex] fits [tex]\( 2 \)[/tex] times into [tex]\( 116 \)[/tex] because [tex]\( 49 \times 2 = 98 \)[/tex].
Write down [tex]\( 2 \)[/tex] above the dividend line next to the [tex]\( 1 \)[/tex].
#### Step 5: Subtract and Find the Remainder
Subtract [tex]\( 98 \)[/tex] from [tex]\( 116 \)[/tex]:
[tex]\[ 116 - 98 = 18 \][/tex]
Since there are no more digits to bring down, [tex]\( 18 \)[/tex] is the remainder.
### Conclusion
The quotient of [tex]\( 606 \div 49 \)[/tex] is [tex]\( 12 \)[/tex] with a remainder of [tex]\( 18 \)[/tex]. Therefore, the result can be written as:
[tex]\[ 606 \div 49 = 12 \text{ R } 18 \][/tex]
or in other terms, [tex]\( 606 = 49 \times 12 + 18 \)[/tex].
